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Novay_Z [31]
3 years ago
10

Sijagsjshshsjwhwbsisjwbshhs

Chemistry
2 answers:
stira [4]3 years ago
7 0

Answer:

fjrjrnrirjrjjrjrjdiejejjdoajwjdoornrkrjrjroenejdjejjejjeujrjrbdjjendjjdjdjeneoapwnsbqkskennskennejdjeccjrjnrjrbbrjkwkwnnsjwjejjejeniebejjdiejejeiwnekwkiejejejj2jekwkwjekwok2mwnwjenrnowo2p1plaks

Anettt [7]3 years ago
5 0

Answer:

Thanks- :D

Explanation:

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The pressure the gas exert the walls of the container will decrease because the gas particles hit the wall of the container
ser-zykov [4K]
The statement is false. The pressure of a gas do not decrease as the gas molecules hit the walls of the container. According to the Kinetic Molecular Theory, collisions of the gas molecules or with the walls of the container are perfectly elastic. This means that energy is not lost as the molecules collide with each other or with the walls of the container.
5 0
4 years ago
Which of the following expresses why water is so important to living organisms
BARSIC [14]
Water keeps living organisms alive
8 0
3 years ago
How many moles of oxygen gas (O2) are in a 2.50 L container at standard temperature and pressure?
Anon25 [30]

Hey there!:

1 mole O2 ----------------- 22.4 L  ( at STP )

( moles O2 ) -------------- 2.50 L

moles O2  = 2.50 * 1 / 22.4

moles O2 = 2.50 / 22.4

moles O2 =  1.12*10⁻¹


Answer B


Hope that helps!

6 0
4 years ago
When 0.250 moles of LiCl are added to 200.0 g of water in a constant pressure calorimeter a temperature change of +11.08°C is ob
Nonamiya [84]

Answer:

3.91 × 10⁴ J/mol

Explanation:

We can calculate the heat of solution using the following expression.

Q = c × m × ΔT

where,

c is the specific heat capacity of the solution

m is the mass of the solution

ΔT is the change in the temperature

The mass of LiCl is:

0.250mol.\frac{42.39g}{mol} =10.6g

The mass of the solution is:

m = mLiCl + mH₂O = 10.6 g + 200.0 g = 210.6 g

Q = c × m × ΔT = (4.184 J g⁻¹ °C⁻¹) × 210.6 g × 11.08 °C = 9763 J

In a constant pressure calorimeter, the molar enthalpy of solution for LiCl is:

\Delta H_{sol}=\frac{9763J}{0.250mol} =3.91 \times 10^{4} J/mol

3 0
3 years ago
WHY IS IT IMPORTANT TO HAVE A LARGE SAMPLE SIZE IN ANY EXPERIMENT?
Anon25 [30]
It is important because if the sample size is smaller, outliers could skew the data more than if it was large.
5 0
3 years ago
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