Answer:
particle size analysis, particle size measurement, or simply particle sizing is the collective name of the technical procedures, or laboratory techniques which determines the size range, and/or the average, or mean size of the particles in a powder or liquid sample.
Explanation:
Answer: D. It is a base because it increases the concentration of hydroxide ions.
Explanation: A base is a substance which dissociates to give hydroxide ions in water.
An acid is a substance which dissociates to give hydrogen ions in water.
So 
is a base as it gives 
ions when dissolved in water.
Answer:
Alluvium
Explanation:
Unlike solid rock Alluvium is loosely compacted, unconsolidated eroded
soil or sediment that has been reshaped by water and redeposited in a non-marine environment. It is typically made up of a various materials, such as fine
silt and clay particles and large sand particles as well as gravel. When alluvial material is consolidated into a lithological unit, or lithified, it is known as an alluvial deposit.
Answer : The temperature in degree Celsius is, 
Explanation :
The conversion used for the temperature from Kelvin to degree Celsius is:
where,
= temperature in Kelvin
= temperature in centigrade
As we are given the temperature in Kelvin is, 2.7
Now we have to determine the temperature in Kelvin.
Therefore, the temperature in degree Celsius is,
Answer:
copper will reach to higher temperature first.
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
The substances with higher value of specific heat capacity require more heat to raise the temperature by one degree as compared the substances having low value of specific heat capacity.For example,
The specific heat capacity of copper is 0.386 j/g. K and for aluminium is 0.900 j/g.K. So, aluminium take a time to increase its temperature by one degree by absorbing more heat while copper will heat up faster by absorbing less amount of heat.
Consider that both copper and aluminium have same mass of 5g and change in temperature is 15 K. Thus amount of heat thy absorbed to raise the temperature is,
For copper:
Q = m.c. ΔT
Q = 5 g× 0.386 j/g K × 15 K
Q = 28.95 j
For aluminium:
Q = m.c. ΔT
Q = 5 g× 0.900 j/g K × 15 K
Q = 67.5 j
we can observe that aluminium require more heat which is 67.5 j to increase its temperature. So it will reach to higher temperature later as compared to copper.
