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suter [353]
2 years ago
8

32 You have two objects made of the same substance. Object 1 is a cube with a mass of 257.7 g. You measure the side of the cube

using a ruler and find it to be 3.17 cm. Object 2 is a sphere with a mass of 128.9 g. You find the volume of the sphere using water displacement. The volume of the water in a graduated cylinder initially is 120.0 mL, and when the sphere is added the new volume is 135.8 mL.
Chemistry
1 answer:
aleksandrvk [35]2 years ago
8 0

The complete question requires that we verify the density of both objects.

The density of object 1 is; 8.1g/cm³ while the density of object 2 is; 8.16g/cm³

<h3>Density of substances</h3>

The density of a substance is given as;

Density = Mass/Volume

Therefore, for Object 1;

  • Volume= l³ (for cubes)

Volume = (3.17)³ = 31.86cm³

Density (1) = 257.7/31.86 = 8.1 g/cm³

For Object 2;

  • Volume = 135.8 - 120 = 15.8mL

  • Volume = 15.8mL = 15.8 cm³

Density = 128.9/15.8

Density = 8.16g/cm³

Read more on density of substances;

brainly.com/question/6838128

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Formula los siguientes compuesto: Dietil eter, Etanol, Propanotriol, Acido Propanodioico, Pentanal, Pentano-2,4-diona, Metanoato
9966 [12]

Answer:

Explanation:

En este caso para formular los compuestos, debes identificar el grupo funcional principal de la molecula. Una vez que eso está hecho, puedes intentar formularlo.

Empezaremos primero identificando el grupo funcional principal de la molécula, para luego formularlo correctamente.

Dietil eter: la terminación eter al final significa que pertenece al grupo de los éteres, el cual tiene como formula general R - O - R.

Etanol: debido a que termina en ol, este grupo pertenece a los alcoholes. Para formularlo solo se dibuja la molecula del etano, junto a un enlace con el grupo OH, como su formula general R - OH.

Propanotriol: igualmente termina en ol, por lo tanto es un alcohol, sin embargo, en este caso, tambien tiene la terminación prefija tri, asi que significa que hay 3 grupos OH en la molecula.

Acido propanodioico: esta es sencilla, porque empieza como acido, y solo hay un grupo funcional que empieza así y son los acidos carboxilicos, es decir, el grupo COOH (R - COOH) que es el carboxilo. Tiene el prefijo di, antes del oico, por lo que son dos carboxilos presentes en la molecula.

Pentanal: el sufijo al, significa que pertenece al grupo de los aldehidos, en este caso, posee el grupo carbonilo H - C = O.

Pentano - 2,4 - diona: la terminación ona significa que pertenece al grupo de las cetonas, (R - CO - R), parecido a los aldehidos, con la diferencia de que tiene grupos alquilos en lugar de un hidrogeno.

Metanoato de metilo: la terminación ato de ilo, pertenece a los esteres, (R - COOR) derivado de los acidos carboxilicos.

De aqui en adelante solo mencionaré los grupos funcionales pues ya se explicó el por que, por sus terminaciones:

Ciclohexano - 1.3 - diol: este pertenece a los alcoholes.

Acido heptanoico: acido carboxilico

Ciclobutil metil eter: eteres

Acetato de etilo: ester

2-metilbenzaldehído: aldehído unido a un grupo aromatico como el benceno.

Ciclohexanona: un ciclo (cadena cerrada) unido a un grupo carbonilo.

Butanona: cetona.

Observa la foto adjunta para que veas la formulación de cada una:

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3 years ago
What changes shape but doesn't change volume
OLEGan [10]
Liquids have a definite volume, but not a definite shape. Hope this helps :)
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3 years ago
How many grams are in 7.32 x 1023 molecules of potassium carbonate (K2CO3)?
tiny-mole [99]

(I leave off the x10^23 because they both will divide out)    Use your per

7 0
2 years ago
When a solution of 0.1 M Mg(NO3)2 was mixed with a limited amount of aqueous ammonia, a light white, wispy solid was observed, i
Ipatiy [6.2K]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of magnesium nitrate and aqueous ammonia (ammonium hydroxide) is given as:

Mg(NO_3)_2(aq.)+2NH_4OH(aq.)\rightarrow Mg(OH)_2(s)+2NH_4NO_3(aq.)

A white precipitate of magnesium hydroxide is formed in the above reaction.

Ionic form of the above equation follows:

Mg^{2+}(aq.)+2NO_3^-(aq.)+2NH_4^+(aq.)+2OH^-(aq.)\rightarrow Mg(OH)_2(s)+2NH_4^+(aq.)+2NO_3^-(aq.)

As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

Mg^{2+}(aq.)+2OH^-(aq.)\rightarrow Mg(OH)_2(s)

Hence, the net ionic equation is written above.

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3 years ago
C12H7Cl3FNaO2 what are them elements in that chemical formula
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Assuming you are asking for the names of the elements in that formula , the answer is

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