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suter [353]
3 years ago
8

32 You have two objects made of the same substance. Object 1 is a cube with a mass of 257.7 g. You measure the side of the cube

using a ruler and find it to be 3.17 cm. Object 2 is a sphere with a mass of 128.9 g. You find the volume of the sphere using water displacement. The volume of the water in a graduated cylinder initially is 120.0 mL, and when the sphere is added the new volume is 135.8 mL.
Chemistry
1 answer:
aleksandrvk [35]3 years ago
8 0

The complete question requires that we verify the density of both objects.

The density of object 1 is; 8.1g/cm³ while the density of object 2 is; 8.16g/cm³

<h3>Density of substances</h3>

The density of a substance is given as;

Density = Mass/Volume

Therefore, for Object 1;

  • Volume= l³ (for cubes)

Volume = (3.17)³ = 31.86cm³

Density (1) = 257.7/31.86 = 8.1 g/cm³

For Object 2;

  • Volume = 135.8 - 120 = 15.8mL

  • Volume = 15.8mL = 15.8 cm³

Density = 128.9/15.8

Density = 8.16g/cm³

Read more on density of substances;

brainly.com/question/6838128

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A solution is made by mixing 55.g of thiophene C4H4S and 65.g of acetyl bromide CH3COBr.
EleoNora [17]

Answer:

Mole fraction of C₄H₄S = 0.55

Explanation:

Mole fraction is moles of solute / Total moles

Total moles are the sum of moles of solute + moles of solvent.

Let's find out the moles of our solute and our solvent.

Mass of solute: 55g

Mass of solvent: 65g

Mol = Mass / molar mass

55 g / 84.06 g/mol = 0.654 moles of C₄H₄S

65 g /123 g/mol = 0.529 moles of C₂H₃BrO

Total moles = 0.654 + 0.529 = 1.183 moles

Mole fraction of thiophene = Moles of tiophene / Total moles

0.654 / 1.183 = 0.55

4 0
3 years ago
Please review the attachment
astra-53 [7]

Answer: The correct answer is -297 kJ.

Explanation:

To solve this problem, we want to modify each of the equations given to get the equation at the bottom of the photo. To do this, we realize that we need SO2 on the right side of the equation (as a product). This lets us know that we must reverse the first equation. This gives us:

2SO3 —> O2 + 2SO2 (196 kJ)

Remember that we take the opposite of the enthalpy change (reverse the sign) when we reverse the equation.

Now, both equations have double the coefficients that we would like (for example, there is 2S in the second equation when we need only S). This means we should multiply each equation (and their enthalpy changes) by 1/2. This gives us:

SO3 —>1/2O2 + SO2 (98 kJ)

S + 3/2O2 —> SO3 (-395 kJ)

Now, we add the two equations together. Notice that the SO3 in the reactants in the first equation and the SO3 in the products of the second equation cancel. Also note that O2 is present on both sides of the equation, so we must subtract 3/2 - 1/2, giving us a net 1O2 on the left side of the equation.

S + O2 —> SO2

Now, we must add the enthalpies together to get our final answer.

-395 kJ + 98 kJ = -297 kJ

Hope this helps!

8 0
3 years ago
Read 2 more answers
What is the percentage error of length measurement of 0.229cm if the correct value is 0.225cm
Mars2501 [29]

Percent error is the difference between the measured and known value, divided by the known value, multiplied by 100%.

So first, we take our measured value, .299 cm, minus our known value, .225 cm.

.299 cm - .225 cm=.004 cm

Next, we divide that by our known value

\frac{.004}{.225}=.0177777778

Finally, multiply your answer by 100

.0177777778 x 100= 1.77777778 %

Round to three significant figures, and you're done.

=1.78 % error



5 0
4 years ago
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When an acid is added to a base, which if the following changes in pH might be observed?
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Im just guessing, so i think is A
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Scientists have observed that hurricanes are strongest over water, and that hurricanes lose momentum and become weak when they r
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Answer:

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