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weqwewe [10]
2 years ago
10

What is the price of $45 art set with 7% tax

Mathematics
1 answer:
olasank [31]2 years ago
5 0

Answer:

$48.15

Step-by-step explanation:

Take 45 and multiply it by 0.07 and you get 3.15. Add that number to 45 and you get 48.15 as your answer

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The French Club is sponsoring a bake sale. If their goal is to raise at least $140, how many pastries must they sell at $3.50 ea
weeeeeb [17]

Let x be the number of pastries they must sell.

$3.50x≥140

This inequality states that for the number of pastries at 3.50 dollars each must be greater than or equal to 140. Solve for x.

3 0
3 years ago
Please help me ......................
jekas [21]

Answer:

n = 18

Step-by-step explanation:

The formula for angle sum of a polygon is S = 180 (n - 2), where S is the sum and n is the sides.

We are given that the sum is 2880, and are trying to find n.

Simply sub in S = 2880,

2880 = 180 (n - 2)

Divide by 180 to get (n - 2) by themselves on the right side,

16 = n - 2

Now add 2 to the other side to get n by itself

18 = n

n = 18

Hope this helped!! Please feel free to ask me if there's anything you don't understand from this working

3 0
3 years ago
Read 2 more answers
Tina has put 15 of her old CDs in a storage crate. How many more CDs can she store in the crate if it can hold no more than 23 C
Lerok [7]
23-15=8 I think the answer is 8


6 0
3 years ago
Read 2 more answers
HELP HELP HELP HELP its hard
Kipish [7]

Step-by-step explanation:

{2}^{x}  -  {x}^{2}

x = 5

{2}^{5}  -  {5}^{2}

2×2×2×2×2-5×5

64-25

39

hope it's helpful ❤❤❤❤❤❤

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8 0
3 years ago
If the scientist is accurate, what is the probability that the proportion of airborne viruses in a sample of 477 viruses would d
melisa1 [442]

Answer:

0.01596

Step-by-step explanation:

A scientist claims that 8% of the viruses are airborne

Given that:

The population proportion p = 8%

The sample size = 477

We can calculate the standard deviation of the population proportion by using the formula:

\sigma_p = \sqrt{\dfrac{p(1-p)}{n}}

\sigma_p = \sqrt{\dfrac{0.8(1-0.8)}{477}}

\sigma_p = \sqrt{\dfrac{0.0736}{477}}

\sigma_p = 0.02098

The required probability can be calculated as:

P(| \hat p - p| >  0.03) = P(\hat p - p< -0.03 \ or \  \hat p - p > 0.03)

= P \bigg ( \dfrac{\hat p -p }{\sqrt{\dfrac{p(1-p)}{n}}} < -\dfrac{0.03}{0.0124}  \bigg ) +  P \bigg ( \dfrac{\hat p -p }{\sqrt{\dfrac{p(1-p)}{n}}} >\dfrac{0.03}{0.0124} \bigg )

= P(Z < -2.41) + P(Z > 2.41)

= P(Z < -2.41) + P(Z < -2.41)

= 2P( Z< - 2.41)

From the  Z-tables;

P(| \hat p - p| >  0.03) = 2 ( 0.00798

P(| \hat p - p| >  0.03) = 0.01596

Thus, the required probability = 0.01596

3 0
3 years ago
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