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Monica [59]
3 years ago
13

B. A hydraulic jack has a ram of 20 cm diameter and a plunger of 3 cm diameter. It is used for lifting a weight of 3 tons. Find

the force required at the plunger.
a. 675.2kgf

b. 67.52kgf

c. 6752.0kgf

d. None of the above
Physics
1 answer:
lozanna [386]3 years ago
4 0

Answer:

option (b)

Explanation:

According to the Pascal's law

F / A = f / a

Where, F is the force on ram, A be the area of ram, f be the force on plunger and a be the area of plunger.

Diameter of ram, D = 20 cm, R = 20 / 2 = 10 cm

A = π R^2 = π x 100 cm^2

F = 3 tons = 3000 kgf

diameter of plunger, d = 3 cm, r = 1.5 cm

a = π x 2.25 cm^2

Use Pascal's law

3000 / π x 100 = f / π x 2.25

f = 67.5 Kgf

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Answer:

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Explanation:

The given parameters are;

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The height level of the lighter construction worker's location = h₁

The height level of the other construction worker's location = h₂ = 2·h₁

The gravitational potential energy, P.E.,  is given as follows;

P.E. = m·g·h

Where;

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g = The acceleration due to gravity

h = The height at which is located

Let P.E.₁ represent the gravitational potential energy of one construction worker and let P.E.₂ represent the gravitational potential energy of the other construction worker

We have;

P.E.₁ = P.E.₂

Therefore;

m₁·g·h₁ = m₂·g·h₂

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We have;

m₁·g·h₁ = m₂·g·2·h₁

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m₂ = (90 kg)/2 = 45 kg

The mass of the other construction worker is 45 kg.

8 0
3 years ago
A spring is used as part of a lift system and follows Hooke's law. If the spring is
salantis [7]

Answer:

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Using the hooke's law equation as follows;

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According to the information given in this question;

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QUESTION -

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