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Monica [59]
3 years ago
13

B. A hydraulic jack has a ram of 20 cm diameter and a plunger of 3 cm diameter. It is used for lifting a weight of 3 tons. Find

the force required at the plunger.
a. 675.2kgf

b. 67.52kgf

c. 6752.0kgf

d. None of the above
Physics
1 answer:
lozanna [386]3 years ago
4 0

Answer:

option (b)

Explanation:

According to the Pascal's law

F / A = f / a

Where, F is the force on ram, A be the area of ram, f be the force on plunger and a be the area of plunger.

Diameter of ram, D = 20 cm, R = 20 / 2 = 10 cm

A = π R^2 = π x 100 cm^2

F = 3 tons = 3000 kgf

diameter of plunger, d = 3 cm, r = 1.5 cm

a = π x 2.25 cm^2

Use Pascal's law

3000 / π x 100 = f / π x 2.25

f = 67.5 Kgf

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uring the investigation of a traffic accident, police find skid marks 89.9 m long. They determine the coefficient of friction be
aivan3 [116]

Answer:

V_{0}=29.68m/s

Explanation:

In order to solve this problem, we must first do a drawing of the situation (see attached picture).

When the brakes of the car were applied, we can see that there was only one horizontal force affecting the vehicle's movement, which was the force of friction. When analyzing the free body diagram we can apply Newton's laws to determine the equations we will use to solve this.

\sum F_{x}=ma

so:

-f=ma

we also know that:

f=N\mu_{k}

so

-N\mu_{k}=ma

we can now solve for the acceleration, so we get:

a=\frac{-N\mu_{k}}{m}

we don't know what the normal force is, so we can find it out by analyzing the vertical forces applied to the car:

\sum F_{y}=0

so we get:

N-W=0

which means that:

N=W

we also know that:

W=mg

so

N=mg

we can substitute this into the first equation so we get:

a=\frac{-mg\mu_{k}}{m}

which simplifies to:

a=-g\mu_{k}

we can now substitute the provided data:

a=(-9.8m/s^{2})(0.5)

which yields:

a=-4.9m/s^{2}

once we got the acceleration, we can use kinematics formulas to solve this, we got the following formula:

a=\frac{V_{f}^{2}-V_{0}^{2}}{2x}

we know the final velocity must be zero, since that's where the car got to a stop, so the formula then becomes:

a=-\frac{V_{0}^{2}}{2x}

we can now solve for the initial velocity, which yields:

V_{0}=\sqrt{-2xa}

so we can now substitute the daa we know, so we get:

V_{0}=\sqrt{-2(89.9m)(-4.9m/s^{2})}

so we get:

V_{0}=29.68m/s

So from this we know that the velocity of the car must have been of at least 29.68m/s when the brakes were applied.

4 0
4 years ago
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anzhelika [568]

Answer:

The average velocity of an object is its total displacement divided by the total time taken. In other words, it is the rate at which an object changes its position from one place to another.

Explanation:

Average velocity is a vector quantity. The SI unit is meters per second. However, any distance unit per any time unit can be used when necessary, such as miles per hour (mph) or kilometer per hour (kmph)

6 0
3 years ago
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A student charges a balloon and then brings it near a metal sphere hanging from the
Hunter-Best [27]

Answer:

B

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_______ occurs as the energy of a photon increases?
kari74 [83]

Answer:

An increase in frequency

Explanation:

A photon is an electromagnetic radiation without mass,as the energy of a photon is increased it frequency also increases.

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F is the frequency measured in Hertz from this a direct relationship exist between the energy and frequency

3 0
4 years ago
A boxed 12.0 computer monitor is dragged by friction 7.50 up along the moving surface of a conveyor belt inclined at an angle of
sasho [114]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

Below is the solution:

W done by Normal = 0. (make the incline flat, Normal force goes directly up: no work done) 
<span>W done by gravity = w*displacement = (11kg*9.8) * 7.5sin(35) = -463J </span>
<span>W done by friction is the opposite of the work done by weight because the object is not moving. Therefore W done by friction = 463J</span>
8 0
4 years ago
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