All categories

3 years ago

Which statement correctly explains mechanical advantage?

Physics

1 answer:

Shtirlitz [24]3 years ago

4 0

I'm not entirely sure but I would think it's A.

You might be interested in

In a World Cup soccer match, Juan is running due north toward the goal with a speed of 7.60 m/s relative to the ground. A teamma

spayn [35]

Answer:

Part a)

$v_{bj} = 11.03 m/s$

Part b)

$\theta = 4.57 degree$ East of South

Explanation:

Part a)

Velocity of Juan is given as

$v_1 = 7.60 m/s \hat j$

velocity of the ball is given as

$v_2 = 12.9(cos31.4 \hat i + sin31.4\hat j)$

now we have

$v_2 = 11\hat i + 6.72\hat j$

Part a)

We need to find velocity of ball with respect to Juan

so it is given as

$v_{bJ} = \vec v_b - \vec v_j$

$v_{bj} = 11\hat i + 6.72 \hat j - 7.6\hat j$

$v_{bj} = 11\hat i - 0.88\hat j$

magnitude of the speed is given as

$v_{bj} = \sqrt{11^2 + 0.88^2}$

$v_{bj} = 11.03 m/s$

Part b)

direction of velocity of the ball

$tan\theta = \frac{v_y}{v_x}$

$tan\theta = \frac{-0.88}{11}$

$\theta = 4.57 degree$ East of South

3 0

2 years ago

Match the glacier feature with its description.

scZoUnD [109]

Answer:

kettles: holes left by glaciers.

cirques: three-sided valleys

erratics: large, out-of-place rocks bouldersleft by glaciers.

drumlins: egg-shaped hills

Explanation: APEX

5 0

3 years ago

Read 2 more answers

What impulse occurs when an average force of 7.0 N is exerted on a cart for 2.5 s ?

makkiz [27]

Answer: $1.7\times 10$

Explanation:

Given

Force $F=7 N$

time interval $t=2.5 s$

Impulse is given by $=Force \times time\ interval\ for\ applied\ force$

$Impulse=7\times 2.5=17.5$

For two significant Figure

$Impulse=1.7\times 10$

7 0

3 years ago

What distance does a police car travel if it is going 3.0 m/s for 20 seconds

Vladimir79 [104]

Answer:

60 meters

Explanation:

If you are going 3 meters in a second, and you are traveling for 20 seconds, you have to multiply

3meters/second*20seconds

cross out the seconds and you have

3 meters*20

60 meters

6 0

2 years ago

It is estimated that uranium is relatively common in the earth's crust, occurring in amounts of 4 g / metric ton. A metric ton i

timama [110]

Answer:

The mass of Uranium present in a 1.2mg sample is $4.8 \cdot 10^{-6}\,mg$

Explanation:

The ration between Uranium mass and total sample mass is: $\frac{4g}{1000kg} =\frac{4g}{1000000g}=\frac{1}{250000}$

For a sample of mass 1.2 mg, the amount of uranium is:

$1.2\, mg \cdot \frac{1}{250000}=4.8 \cdot 10^{-6}\,mg$

7 0

3 years ago