Answer:
v₀ = 6.64 m / s
Explanation:
This is a projectile throwing exercise
x = v₀ₓ t
y = y₀ + v_{oy} t - ½ g t²
In this case they indicate that y₀ = 1.8 m and the point of the basket is x=4.9m y = 3.0 m
the time to reach the basket is
t = x / v₀ₓ
we substitute
y- y₀ =
y - y₀ = x tan θ -
we substitute the values
3 -1.8 = 3.0 tan 60 -
1.2 = 5.196 - 176.4 1 / v₀²
176.4 1 / v₀² = 3.996
v₀ =
v₀ = 6.64 m / s
Forces always work in the direction of their application.
Eg- Gravitational forces acts downwards due to the earth's pull.
The box is kept in motion at constant velocity by a force of F=99 N. Constant velocity means there is no acceleration, so the resultant of the forces acting on the box is zero. Apart from the force F pushing the box, there is only another force acting on it in the horizontal direction: the frictional force

which acts in the opposite direction of the motion, so in the opposite direction of F.
Therefore, since the resultant of the two forces must be zero,

so

The frictional force can be rewritten as

where

,

. Re-arranging, we can solve this equation to find

, the coefficient of dynamic friction:
2 atoms of P (phosphorus) and 5 atoms of O (oxygen)
Explanation:
The chemical formula of a generic compound is written as

where
A and B are the symbols of the elements contained in the compound
n and m are the number of atoms of each element, A and B respectively
In this problem, the compound given is

where:
- P is the symbol of the chemical element phosphorus
- O is the symbol of the chemical element oxygen
We see that the number following P is 2, so there are 2 atoms of phosphorus, while the number following O is 5, so there are 5 atoms of oxygen.
Learn more about compounds here:
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