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OLEGan [10]
3 years ago
8

A barge of mass 5.00 ×104 kg is pulled along the Erie Canal by two mules, walking along towpaths parallel to the canal on either

side of it. The ropes harnessed to the mules make angles of 45.0° to the canal. Each mule is pulling on its rope with a force of 1.10 kN. How much work is done on the barge by both of these mules together as they pull the barge 141.0 m along the canal?
Physics
1 answer:
boyakko [2]3 years ago
5 0

Answer:  219,344.5 j

Explanation:

from the question we have the following parameters

mass of barge (m) = 5 x 10^4 kg

angle of ropes (θ) = 45 degrees

force by each mule (F1) = 1.10 kN = 1100 N

force by each mule (F2) = 1.10 kN = 1100 N

distance (s) = 141 m

work done by the mules = force x cos θ x distance

since we are calculating the force of both mules we have to both mules before we can use in the equation

force = 1100 + 1100 = 2200 N

work done =  2200 x cos (45) x 141

work done = 219,344.5 j

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Answer:

76 minutes.

Explanation:

There are 60 minutes in an hour + 16 minutes= 76 minutes.

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3 years ago
The radius of the aorta is «10 mm and the blood flowing through it has a speed of about 300 mm/s. A capillary has a radius of ab
stealth61 [152]

Answer:

(I). The effective cross sectional area of the capillaries is 0.188 m².

(II). The approximate number of capillaries is 3.74\times10^{9}

Explanation:

Given that,

Radius of aorta = 10 mm

Speed = 300 mm/s

Radius of capillary r=4\times10^{-3}\ mm

Speed of blood v=5\times10^{-4}\ m/s

(I). We need to calculate the effective cross sectional area of the capillaries

Using continuity equation

A_{1}v_{1}=A_{2}v_{2}

Where. v₁ = speed of blood in capillarity

A₂ = area of cross section of aorta

v₂ =speed of blood in aorta

Put the value into the formula

A_{1}=A_{2}\times\dfrac{v_{2}}{v_{1}}

A_{1}=\pi\times(10\times10^{-3})^2\times\dfrac{300\times10^{-3}}{5\times10^{-4}}

A_{1}=0.188\ m^2

(II). We need to calculate the approximate number of capillaries

Using formula of area of cross section

A_{1}=N\pi r_{c}^2

N=\dfrac{A_{1}}{\pi\times r_{c}^2}

Put the value into the formula

N=\dfrac{0.188}{\pi\times(4\times10^{-6})^2}

N=3.74\times10^{9}

Hence, (I). The effective cross sectional area of the capillaries is 0.188 m².

(II). The approximate number of capillaries is 3.74\times10^{9}

3 0
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1. What are the three ways an object can accelerate?
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Explanation:

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What Organ filters the blood to remove the waste
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Clara rushes 30m to a truck then turns and walks back. Total travel is 120s what is her average velocity?
navik [9.2K]

Taking into account the definition of velocity, Clara's average velocity is 0.5 m/s.

<h3>Definition of velocity</h3>

Velocity is a physical magnitude that relates the displacement of an object, the time it takes to make this change in position and direction. So it is considered a vector magnitude.

In other words, the velocity can be defined as the amount of space traveled per unit of time with which a body moves, considering the direction, and can be calculated using the expression:

velocity= distance traveled÷ time

<h3>Average velocity of Clara</h3>

Clara rushes 30 m to a truck then turns and walks back. Total travel is 120s. Then, you know:

  • distance traveled= 30m rushing + 30m walking back= 60 m
  • time= 120 s

Replacing in the definition of velocity:

velocity= 60 m÷ 120 s

Solving:

<u><em>velocity= 0.5 m/s</em></u>

Finally, Clara's average velocity is 0.5 m/s.

Learn more about velocity:

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#SPJ1

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