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zepelin [54]
3 years ago
11

You and your friends find a rope that hangs down 11 m from a high tree branch right at the edge of a river. You find that you ca

n run, grab the rope, swing out over the river, and drop into the water. You run at 2.0 m/s and grab the rope, launching yourself out over the river.
Required:
How long must you hang on if you want to drop into the water at the greatest possible distance from the edge?
Physics
1 answer:
horsena [70]3 years ago
4 0

Answer:

if you want to drop into the water at the greatest possible distance from the edge, you must hang for 1.662s.

Explanation:

The time period of the oscillation is,

T = 2\pi \sqrt{ \frac{I} {g }

T = 2\pi \sqrt{\frac{11}{9.8} } \\\\T= 6.65 s

This would be the time taken for the person to move from.

The duration of time he hangs over the river be one-fourth of the time period.

Here,

t= \frac{T}{4}  \\\\t=\frac{6.65}{4}\\\\t = 1.662 s

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hockey puck slides across the ice with an initial velocity of 7.2 m/s. It has a deceleration of 1.1 m/s2 and is traveling toward
dimulka [17.4K]

For this use the formula:

d = Vo * t - (at^2) / 2

Clearing t:

t = d/(v + 0.5*a)

Replacing:

t = 5 m / (7.2 m/s + 0.5 * (-1.1 m/s²)

Resolving:

t = 5 m / (7.2 m/s + (-0.55 m/s²)

t = 5 m / 6.65 m/s

t = 0.75 s

Result:

The time will be <u>0.75 seconds.</u>

7 0
3 years ago
Read 2 more answers
The steps below describe how you hear. number the steps in the correct order. the first one is done for you
NNADVOKAT [17]

3

1

2

4

6

5

7

Hope this helps! : )

6 0
3 years ago
What is the smallest value of n for which the wavelength of a Balmer series line is less than 400 nm
Natasha_Volkova [10]

Answer:

The smallest value is n= 2

Explanation:

The balmer equation is given below

1/λ = R(1/4 - 1/n₂²).

R= 1.0973731568508 × 10^7 m^-1

λ= 400*10^-9 m

(400*10^-9)= 1.0973731568508 × 10^7 (1/4-1/n²)

(400*10^-9)/1.0973731568508 × 10^7

= 1/4 - 1/n²

364.51 *10^-16= 1/4 - 1/n²

1/n²= 1/4 -364.51 *10^-16

1/n² = 0.25-3.6451*10^-14

1/0.25= n²

4= n²

√4= n

2= n

The smallest value is N= 2

7 0
3 years ago
An AC generator supplies 44 rms volts to a 60-Ω resistor at 60 Hz. What is the maximum current in the resistor?
Brilliant_brown [7]

Answer:

1.0639 A

Explanation:

We have given rms voltage V = 44 volt

Resistance = 60 ohm

According to ohm's law V=iR

So 44=i\times 60

i=\frac{44}{60}=0.7333A this is the rms current but we have to find the maximum current

So maximum current i_m=\sqrt{2}i_{rms}=1.414\times 0.7333=1.03693A

8 0
4 years ago
If someone can write everything on this graph, they shall get points.
Zarrin [17]

Answeill give it a go i guess

Explanation:

Year on Gravestone Thickness at bottom Time of weathering AOW

         1758                          78.5                               258                2.4

         1766                          82.5                              79.6                2.4

         1758                          78.5                               258                2.4

         1758                          78.5                               258                2.4

         1758                          78.5                               258                2.4

         1758                          78.5                               258                2.4

         1758                          78.5                               258                2.4

         1758                          78.5                               258                2.4

         1758                          78.5                               258                2.4

         1758                          78.5                               258                2.4

         1758                          78.5                               258                2.4 nvm got lazy

         

3 0
3 years ago
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