#2
As it is given here
initial speed is
![v_i = 6 m/s](https://tex.z-dn.net/?f=v_i%20%3D%206%20m%2Fs)
After 4 seconds the final speed is
![v_f = 14 m/s](https://tex.z-dn.net/?f=v_f%20%3D%2014%20m%2Fs)
so here we can use the formula of acceleration using kinematics
![a = \frac{v_f - v_i}{t}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7Bv_f%20-%20v_i%7D%7Bt%7D)
![a = \frac{14 - 6}{4}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B14%20-%206%7D%7B4%7D)
![a = 2 m/s^2](https://tex.z-dn.net/?f=a%20%3D%202%20m%2Fs%5E2)
so here it will accelerate at 2 m/s^2 rate.
#3
As it is given here
initial it starts from rest
![v_i = 0 m/s](https://tex.z-dn.net/?f=v_i%20%3D%200%20m%2Fs)
After 2.5 seconds the final speed is
![v_f = 15 m/s](https://tex.z-dn.net/?f=v_f%20%3D%2015%20m%2Fs)
so here we can use the formula of acceleration using kinematics
![a = \frac{v_f - v_i}{t}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7Bv_f%20-%20v_i%7D%7Bt%7D)
![a = \frac{15 - 0}{2.5}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B15%20-%200%7D%7B2.5%7D)
![a = 6 m/s^2](https://tex.z-dn.net/?f=a%20%3D%206%20m%2Fs%5E2)
so here it will accelerate at 6 m/s^2 rate.
#4
i think question is not correct as in first line it is saying about a bag of trash and then in next line it is asking for the position of Jumper and bridge.
Answer:
13.33 or 13 1/3m/s (meters per second)
Explanation:
In physics, we use the basic units of meters and seconds. So first convert (km) into meters (m) and also hours and minutes into seconds (s). We end up with 120000m and 9000s. Then divide the 120000m by the 9000s and you end up with 13.33 or 13 1/3 m/s.
The time needed for the hammer to reach the surface of the Earth is 3.54 s.
<h3>
Time of motion of the hammer</h3>
The time of motion is calculated as follows;
t = √(2h/g)
where;
- h is height of fall
- g is acceleration due to gravity
t = √(2 x 10 / 1.6)
t = 3.54 s
Thus, the time needed for the hammer to reach the surface of the Earth is 3.54 s.
Learn more about time of motion here: brainly.com/question/2364404
#SPJ1
Answer:
If by 1.5 MJ you mean 1.5E6 Joules then
W = P t = power X time
W / t = P power
P = 1.5E6 J / 600 sec = 2500 J / s
P = I V
a) I = 2500 J/s / (240 J/c) = 10.4 C / sec = 10.4 amps
b) Q = I t = 10.4 C / sec * 300 sec = 3120 Coulombs
c) E = P * t = 2500 J / sec * 100 hr * 3600 sec / hr = 9.0E8 Joules