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shepuryov [24]
3 years ago
5

Calculate the residuals.

Mathematics
1 answer:
Brrunno [24]3 years ago
7 0

Answer:To find a residual you must take the predicted value and subtract it from the measured value.

Step-by-step explanation:

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How much time has passed to the nearest quarter hour 7:56am-12:22pm
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Answer: 4 hours and 24 minutes

Step-by-step explanation:

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Use the Pythagorean Theorem to find the missing length and then round the
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C=10
a square (36) + b square (64) = c square (100)
The square root of 100 is 10
3 0
3 years ago
Which of the following expressions is a correct interpretation of the expression 2-(-7)
Arte-miy333 [17]

Answer:

B

Step-by-step explanation:

Because you are subtracting a negative number from a positive number, the two negatives will cancel each other out and it will move to the right.

7 0
3 years ago
Jerry bought 72 sticks of gum. There are 8 sticks of gum in a package. Draw a table using the guess, check and revise strategy t
notka56 [123]

Answer: Make a chart that has 2 rows of 10 boxes each and copy this info below.

Step-by-step explanation: Good luck! :D

Packages - Sticks of gum

1 - 8

2 - 16

3 - 24

4 - 32

5 - 40

6 - 48

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8 0
3 years ago
What is the value of a?<br> 5 units <br> 5 1/3 units <br> 6 2/3 units<br> 7 units
allsm [11]

<u>Answer:</u>

Value of a = 5 \frac{1}{3}

<u>Explanation:</u>

This complete Question can be solved via Pythagoras Theorem.

Pythagoras Theorem says that in a right angled triangle, the square of the side which is opposite to the right angle is equal to the squares of both adjacent sides which make the right angle.

So in the given figure, considering triangle XZW, right angled at W, (a+3)^{2} = b^{2} + c^{2}. Consider this as Equation 1

Also Considering triangle WYZ right angled at Y, c^{2} = 3^{2} + 4^{2}, and hence we can calculate the value of c = \sqrt{9+16} = \sqrt{25} = 5

Considering triangle WXY right angled at Y, b^2 = a^2 + 4^2 = a^2 + 16. Consider this as Equation 2.

Substituting value of c in Equation 1, we get as follows:

(a+3)^{2} = b^{2} + c^{2}

(a+3)^{2} = b^{2} + 5^{2}

(a+3)^{2} = b^{2} + 25

a^2 + 3^2 + 2 \times a \times 3 = b^{2} + 25

a^2 + 9 + 6 \times a = b^{2} + 25

a^2 + 6 \times a = b^{2} + 25-9

a^2 + 6 \times a = b^{2} + 16

Consider this as Equation 3

Substituting Equation 2 in Equation 3.

a^2 + 6 \times a = a^2 + 16 + 16

+ 6 \times a = 32

Hence a = \frac{32}{6} = 5 \frac{1}{3}

5 0
3 years ago
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