The y intercept and the gradient
Answer:
1/4
Step-by-step explanation:
3 out of 12 stored over 10:
3 / 12
simplify
1/4
3x+2=x+8
Slandered Form
2x-6=0
Factorizations
2(x-3)=0
Solutions
x=6/2=3 (6 divided by 2 = 3)
Answer:
Length:8 m
Width:3 m
Step-by-step explanation:
<u><em>The complete question is</em></u>
If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the rectangle, and the hypotenuse is 5 meters). How do you solve for L and W, the dimensions of the rectangle.
step 1
<em>Perimeter of rectangle</em>
we know that
The perimeter of rectangle is equal to
![P=2(L+W)](https://tex.z-dn.net/?f=P%3D2%28L%2BW%29)
we have
![P=22\ m](https://tex.z-dn.net/?f=P%3D22%5C%20m)
so
![22=2(L+W)](https://tex.z-dn.net/?f=22%3D2%28L%2BW%29)
Simplify
-----> equation A
step 2
Perimeter of triangle
The perimeter of triangle is equal to
![P=\frac{L}{2}+W+5](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BL%7D%7B2%7D%2BW%2B5)
![P=12\ m](https://tex.z-dn.net/?f=P%3D12%5C%20m)
so
![12=\frac{L}{2}+W+5](https://tex.z-dn.net/?f=12%3D%5Cfrac%7BL%7D%7B2%7D%2BW%2B5)
Multiply by 2 both sides
![24=L+2W+10](https://tex.z-dn.net/?f=24%3DL%2B2W%2B10)
----> equation B
Solve the system of equations by graphing
Remember that the solution is the intersection point both graphs
using a graphing tool
The solution is the point (8,3)
see the attached figure
therefore
The dimensions of the rectangle are
Length:8 m
Width:3 m