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jonny [76]
3 years ago
7

Calculate the atomic mass of Carbon if the two common isotopes of carbon have masses of

Chemistry
1 answer:
Mars2501 [29]3 years ago
5 0

Answer:

Average atomic mass of carbon = 12.01 amu.

Explanation:

Given data:

Abundance of C¹² = 98.89%

Abundance of C¹³ = 1.11%

Atomic mass of C¹² = 12.000 amu

Atomic mass of C¹³ = 13.003 amu

Average atomic mass = ?

Solution:

Average atomic mass of carbon = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass of carbon = (12.000×98.89)+(13.003×1.11) /100

Average atomic mass of carbon=  1186.68 + 14.43333 / 100

Average atomic mass of carbon = 1201.11333 / 100

Average atomic mass of carbon = 12.01 amu.

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Compound.

Because compound is a substance formed by a chemical reaction of two or more separate elements. If a compound is separated, it would become two or more different substances instead of similar ones.

Wish this helps.

Bella from BOC Sciences

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3 years ago
Carbon dioxide and water vapor are variable gases because
ehidna [41]

Answer:

Their amount is not consistent at all parts of the atmosphere

Explanation:

Carbon dioxide and water vapor exists as variable gases in the atmosphere because their amount varies from one part to the other.

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Hydrogen can be obtained economically as a byproduct in the electrolysis of
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<span>Hydrogen can be obtained economically as a byproduct in the electrolysis of "brine".
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A solution of sodium chloride (NaCl)and water (H2O) refers to the brine.The procedure of electrolysis includes utilizing an electric current to achieve a synthetic change and make new chemicals. The electrolysis of brine is a huge scale process used to make chlorine from salt, so  three important chemicals, NaOH, Cl2, H2, can be gotten by electrolyzing brine.
8 0
3 years ago
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A sample of water is heated from 60.0 °C to 75.0°C by the addition of 140 j of
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Mass of the water : 2.23 g

<h3>Furter explanation</h3>

Heat

Q = m.c.Δt

m= mass, g

c = heat capacity, for water : 4.18 J/g° C.

ΔT = temperature

Q= 140 J

Δt = 75 - 60 = 15

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5 0
2 years ago
When methyloxirane is treated with HBr, the bromide ion attacks the less substituted position. However, when phenyloxirane is tr
konstantin123 [22]

Answer:

See explanation and picture below

Explanation:

First, in the case of methyloxirane (Also known as propilene oxide) the mechanism that is taking place there is something similar to a Sn2 mechanism. Although a Sn2 mechanism is a bimolecular substitution taking place in only step, the mechanism followed here is pretty similar after the first step.

In both cases, the H atom of the HBr goes to the oxygen in the molecule. You'll have a OH⁺ in both. However, in the case of methyloxirane the next step is a Sn2 mechanism step, the bromide ion will go to the less substitued carbon, because the methyl group is exerting a steric hindrance. Not a big one but it has a little effect there, that's why the bromide will rather go to the carbon with more hydrogens. and the final product is formed.

In the case of phenyloxirane, once the OH⁺ is formed, the next step is a Sn1 mechanism. In this case, the bond C - OH⁺ is opened on the side of the phenyl to stabilize the OH. This is because that carbon is more stable than the carbon with no phenyl. (A 3° carbon is more stable than a 2° carbon). Therefore, when this bond opens, the bromide will go there in the next step, and the final product is formed. See picture below for mechanism and products.

4 0
3 years ago
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