Answer:
Ytterbium is a chemical element with the symbol Yb and atomic number 70. It is the fourteenth and penultimate element in the lanthanide
Answer:
carbon dioxide
Explanation:
Carbon burns in oxygen to form carbon dioxide. Since hydrocarbon fuels only contain two elements, we always obtain the same two products when they burn. In the equation below methane (CH 4) is being burned. The oxygen will combine with the carbon and the hydrogen in the methane molecule to produce carbon dioxide (CO 2) and water (H 2O).
Carbon, as graphite, burns to form gaseous carbon (IV) oxide (carbon dioxide), CO2. ... When the air or oxygen supply is restricted, incomplete combustion to carbon monoxide, CO, occurs. 2C(s) + O2(g) → 2CO(g) This reaction is important. When one mole of carbon is exposed to some energy in the presence of one mole of oxygen gas, one mole of carbon dioxide gas is produced. This reaction is a combustion reaction.
Answer:
0.225 mol = 0.23 mol to 2 significant figures
Explanation:
Calculate the moles of oxygen needed to produce 0.090 mol of water
The equation of the reaction is given as;
2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O
From the equation of the reaction;
5 mol of O2 produces 2 mol of H2O
x mol of O2 produces 0.090 mol of H2O
5 = 2
x = 0.090
x = 0.090 * 5 / 2
x = 0.225 mol
The sealed bottle would have the highest concentration of Carbon Dioxide because the pressure is highest and there was no time for diffusion.
Answer:
1.0 L
Explanation:
Given that:-
Mass of
= 
Molar mass of
= 64.099 g/mol
The formula for the calculation of moles is shown below:

Thus,


According to the given reaction:-

1 mole of
on reaction forms 1 mole of 
0.0396 mole of
on reaction forms 0.0396 mole of 
Moles of
= 0.0396 moles
Considering ideal gas equation as:-

where,
P = pressure of the gas = 742 mmHg
V = Volume of the gas = ?
T = Temperature of the gas = ![26^oC=[26+273]K=299K](https://tex.z-dn.net/?f=26%5EoC%3D%5B26%2B273%5DK%3D299K)
R = Gas constant = 
n = number of moles = 0.0396 moles
Putting values in above equation, we get:

<u>1.0 L of acetylene can be produced from 2.54 g
.</u>