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3 years ago

For lunch yesterday micah bought hotdog for 1.79 potato chips for .89 milkshake for 1.15 how much lunch cost not including tax

Mathematics

1 answer:

Alla [95]3 years ago

7 0

1.79+0.89+1.15 = 3.83

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Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-

Shtirlitz [24]

Answer:

The number c is 2.

Step-by-step explanation:

Mean Value Theorem:

If f is a continuous function in a bounded interval [0,4], there is at least one value of c in (a,b) for which:

$f(c) = \frac{1}{b-a}\int\limits^a_b {f(x)} \, dx$

In this problem, we have that:

$f(x) = x, a = 0, b = 4$

So $f(c) = c$

----------

$f(c) = \frac{1}{b-a}\int\limits^a_b {f(x)} \, dx$

$c = \frac{1}{4-0}\int\limits^0_4 {x} \, dx$

$c = \frac{1}{4-0}*8$

$c = 2$

The number c is 2.

3 0

3 years ago

Well when you do a problem and it's multiplication and you have to us your math skills and then when you get it wrong don't that

masha68 [24]

Not necessarily. You could have done your multiplication wrong. Or in some cases, yes, you could have to use another skill. For example, you can't solve an optimization problem with addition, you need some calculus skills under your belt.

8 0

3 years ago

Hi bro sorry to bother you but I have a question it is ok . Ok then so 875x975=

mel-nik [20]

Answer:

853,125

Step-by-step explanation:

Umhhh u can use a calculator… or write it down and slowly break down solve it like that.

Hope this helps, good luck! ;)

4 0

3 years ago

Read 2 more answers

What are some study habits that helped? I have tried loads of ideas but I just can't to seem to find one that works for me.

Leviafan [203]

For me being 100% honest:

grade 9-11 no homework, pay attention in class and study night before.

Grade 12: pay attention more in class, do some homework when concepts hard, study night before.

Uni: Read notes, do class homework, read textbook, study week before.

7 0

4 years ago

Can anyone help me with this please

olga_2 [115]

Hi there!

$\large\boxed{\frac{1}{4}, -\frac{3}{2}}$

13y² + 10y - 3 = 5y²

Begin by moving all terms to one side:

13y² + 10y - 3 - 5y² = 0

Combine like terms:

8y² + 10y - 3 = 0

Factor using the guess-and-check method.

(4y - 1)(2y + 3) = 0

Set each factor equal to 0 to find the solutions:

4y - 1 = 0

4y = 1

y = 1/4

2y + 3 = 0

2y = -3

y = -3/2

8 0

3 years ago