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3 years ago

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There are 4 kings in a standard deck of 52 playing cards. What is the probability if randomly selecting a card that is NOT a kin

g?
A. 1/52
B. 1/13
C. 1/2
D. 12/13

2 answers:

antoniya [11.8K]3 years ago

7 0

D I know is D but not really

Anit [1.1K]3 years ago

7 0

A there’s 52 cards so there’s a 1 In 52 chance... can I get brain test

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Determine the domain for the graphed function:<br> Please help meeee

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Answer:

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First, domain refers to the x axis. So you would find the lowest number on the X axis, -2, and then you look at the kind of dot on that number. It is an open dot, which means that it is all the numbers up to -2, but does not include -2. Then you find the highest number, in this case 2. Looking at the dot that is marking it, it is a closed dot, meaning it includes the number 2. So the domain would be numbers between -2 and 2, but does not include -2. all numbers greater than -2, x, all numbers less than and equal to 2.

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3 years ago

Use the equation Y= 11 - 5X to find y when x=7.

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Answer:

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Step-by-step explanation:

4 members are going to be chosen:

M1 - M2 - M3 - M4

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Initially, we have 15 students, of which 10 have none experience. So the probability that M1 is chosen as a student with no experience is $\frac{10}{15}$ .

Then, there are 14 students, of which 9 have no experience. So the probability that M2 is chosen as a student with no experience is $\frac{9}{14}$ .

For the third member, there are 13 students, of which 8 have no experience. So the probability that M3 is chosen as a student with no experience is $\frac{8}{13}$ .

For the last member, there are 12 students, of which 7 have no experience. So the probability that M4 is chosen as a student with no experience is $\frac{7}{12}$ .

What is the probability that none of the members chosen for the team have any competition experience?

This is

$P = \frac{10}{15}*\frac{9}{14}*\frac{8}{13}*\frac{7}{12} = 0.1538$

The correct answer is:

A) 0.1538

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3 years ago