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2 years ago

What is the simplest form of 2(sqr rt) 3/ (sqr rt) 6??

Mathematics

1 answer:

eduard2 years ago

5 0

Answer:

Option A will be your answer

Step-by-step explanation:

hope it's helpful...

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Selmas class making a care package to give to victims of a natural disaster.Selma packs one box in 5 minutes and has already pac

bixtya [17]

Each of them need to work 105 minutes more in order to have packed the same number of boxes.

Explanation

Suppose, they need to work for $x$ minutes more in order to have packed the same number of boxes.

Selma packs one box in 5 minutes and Trudy packs one box in 7 minutes.

So, the number of boxes packed by Selma in that $x$ minutes $=\frac{x}{5}$ and the number of boxes packed by Trudy in $x$ minutes $=\frac{x}{7}$

Given that, Selma and Trudy have already packed 12 and 18 boxes.

Now if each of them packed the same number of boxes, then the equation will be......

$12+\frac{x}{5}=18+\frac{x}{7}\\ \\ \frac{x}{5}-\frac{x}{7}= 18-12\\ \\ \frac{7x-5x}{35}=6\\ \\ \frac{2x}{35}=6\\ \\ 2x= 210\\ \\ x= \frac{210}{2}=105$

So, each of them need to work 105 minutes more in order to have packed the same number of boxes.

6 0

3 years ago

in a box of chocolates, 1/5 of the chocolates contain nuts. the rest of the chocolates do not contain nuts. write down the ratio

valina [46]

Answer:

The ratio of the number of chocolates that contain nuts to the number of chocolates = 1:4

Step-by-step explanation:

The parameters given are;

Proportion of the box of chocolates that contain nuts = 1/5

Proportion of the box of chocolates that do not contain nuts = 1 - 1/5 = 4/5

Therefore, we have in a box of chocolates with five chocolates;

The number of chocolates that contain nuts = 1

The number of chocolates that do not contain nuts = 4

Which gives the ratio of the number of chocolates that contain nuts to the number of chocolates as 1:4.

4 0

3 years ago

What is the distance from C to D? A. 5 units B. 1 unit C. 25 units D. 7 units

Vera_Pavlovna [14]

Answer:

Option A

Step-by-step explanation:

According to the distance formula , for any 2 points P & Q whose coordinates are (x¹ , y¹) and (x² , y²) respectively. So ,

$PQ = \sqrt{(x^{2} - x^{1} )^{2} + (y^{2} - y^{1})^{2} }$

NOTE = HERE x² , y² DOESN'T MEAN THE SQUARES OF x & y . THEY ARE JUST COORDINATES.

According to the question ,

Coordinate of C = (2 , -1)

Coordinate of D = (5 , 3)

Using distance formula ,

$CD = \sqrt{(5-2)^{2} + (3 -(-1))^{2} }$

$=> CD = \sqrt{3^{2} + 4^{2} } = \sqrt{9 + 16} = \sqrt{25} = 5$

5 0

3 years ago

Use the distributive property to remove the parentheses -2(4w-2v-1)

yawa3891 [41]

Answer: -8w+2v+2

Step-by-step explanation:

8 0

1 year ago

The function f(x) is defined below. What is the end behavior of f(x) ?

Dominik [7]

1363.xs and nun of yourrrt bennies

8 0

2 years ago