Answer:
66.4g
Explanation:
Given parameters:
Mass of AgNO₃ = 69.1g
Unknown:
Mass of Ag₂CrO₄
Solution:
2AgNO₃+ Na₂CrO₄ ⟶ Ag₂CrO₄ + 2NaNO₃
The given equation is balanced.
To solve this problem, solve from the known to the unknown;
1. Find the number of moles of AgNO₃;
Number of moles =
atomic mass of Ag = 107.9g/mol
N = 14g/mol
O = 16g/mol
Molar mass of AgNO₃ = 107.9 + 14 + 3(16) = 169.9g/mol
Number of moles = = 0.41moles
2. From the balanced equation;
2 moles of AgNO₃ produced 1 moles of Ag₂CrO₄ ;
0.41 moles of AgNO₃ will produce = 0.2moles of Ag₂CrO₄
3:
Mass of Ag₂CrO₄ = number of moles x molar mass
Atomic mass of Ag = 107.9g/mol
Cr = 52g/mol
0 = 16g/mol
Molar mass = 2(107.9) + 52 + 4(16) = 331.8g/mol
so, mass of Ag₂CrO₄ = 0.2 x 331.8 = 66.4g
Neutrons are very important in provide stability for an atom. When atoms are created by fusion, neutrons are included in this process. Because protons don't like each other and repel each other that's where neutrons come in.
Answer is (3) - metalloid
Elements in group 14 can be classified as non metals, metalloid and metals. Group 14 has C, Si, Ge, Sn and Pb as its elements. C is a non metal. Si and Ge are metalloids while Sn and Pb are metals.
Metalloids are elements which share both non-metallic and metallic characteristics.
The element in group 14, period 3 on the periodic table is Si. Si is a semiconductor means Si can conduct electricity but not good as metals. Conducting electricity ia one of metallic property.
The net pay should be used for creating your budget.
<h3>What is net pay?</h3>
Your net pay is your take-home pay after the deduction of taxes.
Your total pay before deducting taxes is what is known as gross pay.
Mathematically;
Net pay = Gross pay - taxes.
Thus, if you going to create a budget for yourself, you should only use the pay that is yours, the net pay. Taxes belong to the government.
Budgeting with your gross pay will leave you with deficits by the time taxes are removed from your pay.
More on gross and net pay can be found here: brainly.com/question/14690804
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Answer:
The molar concentration of Cu²⁺ in the initial solution is 6.964x10⁻⁴ M.
Explanation:
The first step to solving this problem is calculating the number of moles of Cu(NO₃)₂ added to the solution:
n = 1.375x10⁻⁵ mol
The second step is relating the number of moles to the signal. We know the the n calculated before is equivalent to a signal increase of 19.9 units (45.1-25.2):
1.375x10⁻⁵ mol _________ 19.9 units
x _________ 25.2 units
x = 1.741x10⁻⁵mol
Finally, we can calculate the Cu²⁺ concentration :
C = 1.741x10⁻⁵mol / 0.025 L
C = 6.964x10⁻⁴ M