Answer:
The answer in the procedure
Step-by-step explanation:
Let
x----> the first number
y----> the second number
we know that
so
-----> equation A
----> equation B
substitute equation A in equation B
Present value, PV = $500
Future value, FV = 2*PV = 2*500 = $1,000
Rate, r = 4% = 0.04
Compounding times in a year, n = 4 (compounded quarterly)
Time, t = ??
The future value expression is stated as:
FV = PV (1+r/n)^nt
Substituting;
1000 = 500 (1+0.04/4)^4t
2 = (1.01)^4t
ln 2 = 4t ln 1.01
0.6931 = 4t* 0.00995
0.6931 = 0.0398t
t = 17.414 years
Time required for the amount to double is 17.41 years.
Answer:
48
Step-by-step explanation:
24
+<u>24</u>
48
- First, line up the numbers and write down the subtracting symbol or addition symbol.
- Second, add the ones place
- Then, add the tens place
- If numbers go onto the hundreds place then add that but if not then your done.
The other integer is 289. To solve first make the equation:
x+y=286
Then you can plug in -3 into one of the variables (it doesn't matter which one you choose)
x-3=286
Then solve for x by adding 3 to both sides of the equation getting you 289
