Ask question

Ask question

All categories

3 years ago

14

What is the are of the parallelogram(look at picture)

1 answer:

victus00 [196]3 years ago

3 0

Answer:

18 cm

Step-by-step explanation:

You might be interested in

Anyone wanna join my arsenal server we have giveaways (nitro and robuxs and etc) and tournaments. In tournaments the winner will

FromTheMoon [43]

Answer:

Sorry, dont have discord

Step-by-step explanation:

Thanks for the points, though, I could use them. Much appreciated. Have a good weekend

8 0

3 years ago

you spin the pointer on the spinner . find the probability that the pointer will stop on a number less then 5 . <3 PLEASE HEL

Dominik [7]

THere are 8 numbers in the spinner out of which 1, 2, 3, 4 (i.e. 4 numbers) are less than 5.
P(less than 5) = 4/8 = 1/2

4 0

3 years ago

An apple falls from a tree that is 21 feet tall. What is the height

Alexeev081 [22]

Answer:

Use the vertical motion model, h = -16t^2 + 21 , t=1 second

h = -16(1) ^2 + 21

h = 5 feet

Step-by-step explanation:

Just plug in the time with t to get your answer in height

4 0

3 years ago

Sin =9/15 . Find tan 0

ELEN [110]

Answer:

c. 9/12

Step by step explanation.

Given: sin = 9/15

and,

$sin = \frac{opp.}{hyp.}$

$tan = \frac{opp.}{adj.}$

thus, find adj. side

by using Pythagoras theorem

${c }^{2} = {a}^{2} + {b}^{2}$

then,

let adj. side be a^

${a}^{2} = {c}^{2} - {b }^{2} \\ {a}^{2} = {15 }^{2} - {9}^{2} \\ {a}^{2} = 144 \\ a = 12$

thus,

adj. side is 12

then,

tan of the angle = 9/12

3 0

3 years ago

Directions: Calculate the area of a circle using 3.14x the radius

Leokris [45]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

Now find the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(2.2)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{}$

$\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 68.89$

$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 4</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 5.8 \div 2$

$\qquad \sf \dashrightarrow \:r = 2.9 \: \: yd$

now, let's calculate area ~

$\qquad \sf \dashrightarrow \:3.14 \times {(2.9)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 8.41$

$\qquad \sf \dashrightarrow \:area \approx26.41 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 5</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 1 \div 2$

$\qquad \sf \dashrightarrow \:r = 0.5 \: \: yd$

Now, let's calculate area ~

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (0.5) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 0.25$

$\qquad \sf \dashrightarrow \:area \approx0.785 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 6</h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(8)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 64$

$\qquad \sf \dashrightarrow \:area = 200.96 \: \: yd {}^{2}$

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

8 0

2 years ago