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3 years ago

The number of outer shell electrons determines the chemical properties of an element?

1 answer:

Ivan3 years ago

3 0

Yes, it is true to a certain that the number of outer shell electrons determines the chemical properties of an element, only because this determines how the element interacts with other elements.

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Please help me with this I need a 10 sentence for it please open the image

Effectus [21]

Answer:

0.08 solar masses

Explanation:

0.08 solar mass is required to support nuclear fusion.

4 0

2 years ago

FREE BRAINLIEST! if you can answer this correctly ill give you brainliest and answer some of the questions you have posted :) th

Gala2k [10]

b) accelerate to the left as much more pressure is pulling it in that direction and on the right however , there is less force .

4 0

3 years ago

A 1.5 kg bird is gliding at a height of 12 m with a speed of 3.8m/s. What is the kinetic energy of the bird, to the nearest joul

Georgia [21]

A 1.5 kg bird is gliding at a height of 12 m with a speed of 3.8m/s. The kinetic energy of the bird is 10.83 joules.

Explanation:

Kinetic energy can be defined as,The kinetic energy (KE) of an object is the energy that the object possesses due to its motion.

The Kinetic energy can be calculated by using formula,

Kinetic Energy: KE = 1/2 (mv 2)

Where, m = Mass, v = Velocity.

Here in this case the bird mass is 1.5kg and is gliding with velocity 3.8m/s

hence, KE= 1/2*(1.5)×(3.8)^2

=0.5×1.5×3.8×3.8

=10.83Joules

5 0

3 years ago

If this atom has a balanced charged, how many protons would you expect to find in this atom?

avanturin [10]

The answer would be C because there is six electrons and so there will be six protons because the amount of protons and electrons have to be the same otherwise it would be an unbalanced particle and you wouldn't be able to touch the object it is in without worrying about something happening

3 0

2 years ago

Read 2 more answers

(a) when rebuilding her car's engine, a physics major must exert 300 n of force to insert a dry steel piston into a steel cylind

Vilka [71]

There are some missing data in the text of the problem. I've found them online:
a) coefficient of friction dry steel piston - steel cilinder: 0.3
b) coefficient of friction with oil in between the surfaces: 0.03

Solution:
a) The force F applied by the person (300 N) must be at least equal to the frictional force, given by:
$F_f = \mu N$
where $\mu$ is the coefficient of friction, while N is the normal force. So we have:
$F=\mu N$
since we know that F=300 N and $\mu=0.3$ , we can find N, the magnitude of the normal force:
$N= \frac{F}{\mu}= \frac{300 N}{0.3}=1000 N$

b) The problem is identical to that of the first part; however, this time the coefficienct of friction is $\mu=0.03$ due to the presence of the oil. Therefore, we have:
$N= \frac{F}{\mu}= \frac{300 N}{0.03}=10000 N$

8 0

3 years ago