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Alex73 [517]
2 years ago
6

A 1500 kg car has an applied forward force of 5000 N and experiences an air resistance of 1250 N. What is the car's acceleration

?
Physics
1 answer:
marshall27 [118]2 years ago
8 0

Answer:

2.33\ m/s^2

Explanation:

<u>Net Force </u>

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

Fn = m.a

Where a is the acceleration of the object.  The net force is the sum of the individual vector forces applied to the object.

The m=1500 Kg car has two horizontal forces applied: the forward force of 5000 N that causes the movement and the air resistance force of 1250 N that opposes motion.

The net force is Fn = 5000 N - 1500 N = 3500 N

To find the acceleration, we solve the equation for a:

\displaystyle a=\frac{Fn}{m}

\displaystyle a=\frac{3500}{1500}

\boxed{a = 2.33\ m/s^2}

The car's acceleration is a = 2.33\ m/s^2

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Maksim231197 [3]

Answer:

The kinetic energy of the particle as it moves through point B is 7.9 J.

Explanation:

The kinetic energy of the particle is:

\Delta K = \Delta E_{p} = q\Delta V

<u>Where</u>:

K: is the kinetic energy

E_{p}: is the potential energy

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\Delta K = q \Delta V= 0.8 \cdot 10^{-3} C*1.5 \cdot 10^{3} V = 1.2 J

Now, the kinetic energy of the particle as it moves through point B is:

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Therefore, the kinetic energy of the particle as it moves through point B is 7.9 J.

I hope it helps you!      

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