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KonstantinChe [14]
3 years ago
15

Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 20 cm apart. The sound

intensity decreases as the distance between the speakers is increased, reaching zero at a separation of 70 cm.
Required:
a. What is the wavelength of the sound?
b. If the distance between the speakers continues to increase, at what separation will the sound intensity again be a maximum?
Physics
1 answer:
krek1111 [17]3 years ago
4 0

Answer:

Explanation:

The path length difference = extra distance traveled

The destructive interference condition is:

\Delta d = (m+1/2)\lambda

where m =0,1, 2,3........

So, ←

\Delta d = (m+1/2)\lamb da9/tex]so [tex]\Delta d = \frac{\lambda}{2}

⇒ λ = 2Δd = 2×10 = 20

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A laser beam is incident at an angle of 33.0° to the vertical onto a solution of cornsyrup in water.(a) If the beam is refracted
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Answer:

1.29649

488.08706 nm

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Explanation:

n denotes refractive index

1 denotes air

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\lambda_0 = 632.8 nm

From Snell's law we have the relation

n_1sin\theta_1=n_2sin\theta_2\\\Rightarrow n_2=\dfrac{n_1sin\theta_1}{sin\theta_2}\\\Rightarrow n_2=\dfrac{1\times sin33}{sin24.84}\\\Rightarrow n_2=1.29649

Refractive index of the solution is 1.29649

Wavelength is given by

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The wavelength of the solution is 488.08706 nm

Frequency is given by

f=\dfrac{c}{\lambda}\\\Rightarrow f=\dfrac{3\times 10^8}{488.08706\times 10^{-9}}\\\Rightarrow f=6.14644\times 10^{14}\ Hz

The frequency is 6.14644\times 10^{14}\ Hz

v=\dfrac{c}{n_2}\\\Rightarrow v=\dfrac{3\times 10^8}{1.29469}\\\Rightarrow v=231715700.28346\ m/s

The speed in the solution is 231715700.28346 m/s

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