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3 years ago

PLZ HURRY WILL GIVE BRAINILEST!!:D

Physics

2 answers:

seraphim [82]3 years ago

8 0

Answer:

its b i did this assignment before

Colt1911 [192]3 years ago

3 0

Answer:

b why is Alice suddenly so thirsty i think

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A 1.70-μF capacitor is charging through a 14.0-Ω resistor using a 10.0- V battery. What will be current when the capacitor has a

RoseWind [281]

Answer:

The current is 0.951 A

Solution:

As per the question:

Capacitance of the capacitor, C = $1.70\mu F$

Resistance of the circuit, R = 14.0 $\Omega$

Voltage of the battery, V = 10.0 V

Now, when the charge become one-fourth of its initial value, the amount of current flowing is given by:

$q' = q(1 - e^{-\frac{t}{\tau}})$ (1)

where

q' = $\frac{q}{4}$

$\tau = RC$

$q' = q(1 - e^{-\frac{t}{RC}})$

$\frac{q}{4} = q(1 - e^{-\frac{t}{RC}})$

$0.25 = (1 - e^{-\frac{t}{RC}})$

$0.75 = e^{-\frac{t}{RC}$

$-\frac{t}{RC} = ln(0.75)$

$-\frac{t}{14\times 1.70\times 10^{- 6}} = - 0.2876$

$t = 6.844\times 10^{- 6} s$

Now,

The current is given by:

$I' = Ie^{-\frac{t}{RC}}$ (2)

Also, $I = \frac{V}{R} = \frac{10}{14} = 0.714 A$

Now, using the value of I = 0.714 A

$I' = 0.714e^{-\frac{6.844\times 10^{- 6}}{14\times 1.70\times 10^{- 6}}} = 0.951 A$

3 0

3 years ago

Read 2 more answers

What is the initial velocity of a remote controlled car which travels 6m in 2 seconds, with an

Gwar [14]

Acceleration =(v-u)/t
Put in values And re arrange gives initial velocity of -2 m/s

5 0

4 years ago

A ray of light incident in air strikes a rectangular glass block of refractive index 1.50, at an angle of incidence of 45°. Calc

balandron [24]

Answer:

Approximately $28^{\circ}$ .

Explanation:

The refractive index of the air $n_{\text{air}}$ is approximately $1.00$ .

Let $n_\text{glass}$ denote the refractive index of the glass block, and let $\theta _{\text{glass}}$ denote the angle of refraction in the glass. Let $\theta_\text{air}$ denote the angle at which the light enters the glass block from the air.

By Snell's Law:

$n_{\text{glass}} \, \sin(\theta_{\text{glass}}) = n_{\text{air}} \, \sin(\theta_{\text{air}})$ .

Rearrange the Snell's Law equation to obtain:

$\begin{aligned} \sin(\theta_{\text{glass}}) &= \frac{n_{\text{air}} \, \sin(\theta_{\text{air}})}{n_{\text{glass}}} \\ &= \frac{(1.00)\, (\sin(45^{\circ}))}{1.50} \\ &\approx 0.471\end{aligned}$ .