Question

Please help me I’m trying to pass

Answer 1

Answer:

$\frac{16}{3}$

Step-by-step explanation:

$h(x) = 3 {x}^{2} - 3 \\ plug \: x = \frac{2}{3} \\ h \bigg( \frac{2}{3} \bigg) = 3\bigg( \frac{2}{3} \bigg) ^{2} - 3 \\ h \bigg( \frac{2}{3} \bigg) = 3 \times \frac{4}{9} - 3\\ h \bigg( \frac{2}{3} \bigg) = \frac{4}{3} - 3 \\ h \bigg( \frac{2}{3} \bigg) = \frac{4 - 9}{3} \\ h \bigg( \frac{2}{3} \bigg) = \frac{ - 5}{3} \\ \\ h(x) = 3 {x}^{2} - 3 \\ plug \: x = h \bigg( \frac{2}{3} \bigg) \\ \\ h \bigg(h \bigg( \frac{2}{3} \bigg) \bigg) = 3.[h \bigg( \frac{2}{3} \bigg)] ^{2} - 3 \\ = 3. \bigg(\frac{ - 5}{3} \bigg)^{2} - 3 \\ = 3 \times \frac{25}{9} - 3 \\ = \frac{25}{3} - 3 \\ = \frac{25 - 9}{3} \\ = \frac{16}{3}$