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True [87]
3 years ago
12

How many electrons does an aluminum ion have? a. 10 b. 13 c. 14 d. 16

Chemistry
2 answers:
LiRa [457]3 years ago
4 0

B.an aluminum ion has 13 electrons

Hope this helps <3

Alexxx [7]3 years ago
4 0

Its 13 if you wanted to know

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Define the term organic farming<br><br>​
wolverine [178]

Answer:

is agriculture that makes healthy food,healthy soil,healthy plants and healthy environments a priority,along with crop productivity

5 0
2 years ago
In the Haber process for ammonia synthesis, K " 0.036 for N 2 (g) ! 3 H 2 (g) ∆ 2 NH 3 (g) at 500. K. If a 2.0-L reactor is char
lisabon 2012 [21]

Answer : The partial pressure of N_2,H_2\text{ and }NH_3 at equilibrium are, 1.133, 2.009, 0.574 bar respectively. The total pressure at equilibrium is, 3.716 bar

Solution :  Given,

Initial pressure of N_2 = 1.42 bar

Initial pressure of H_2 = 2.87 bar

K_p = 0.036

The given equilibrium reaction is,

                              N_2(g)+H_2(g)\rightleftharpoons 2NH_3(g)

Initially                   1.42      2.87             0

At equilibrium    (1.42-x)  (2.87-3x)     2x

The expression of K_p will be,

K_p=\frac{(p_{NH_3})^2}{(p_{N_2})(p_{H_2})^3}

Now put all the values of partial pressure, we get

0.036=\frac{(2x)^2}{(1.42-x)\times (2.87-3x)^3}

By solving the term x, we get

x=0.287\text{ and }3.889

From the values of 'x' we conclude that, x = 3.889 can not more than initial partial pressures. So, the value of 'x' which is equal to 3.889 is not consider.

Thus, the partial pressure of NH_3 at equilibrium = 2x = 2 × 0.287 = 0.574 bar

The partial pressure of N_2 at equilibrium = (1.42-x) = (1.42-0.287) = 1.133 bar

The partial pressure of H_2 at equilibrium = (2.87-3x) = [2.87-3(0.287)] = 2.009 bar

The total pressure at equilibrium = Partial pressure of N_2 + Partial pressure of H_2 + Partial pressure of NH_3

The total pressure at equilibrium = 1.133 + 2.009 + 0.574 = 3.716 bar

6 0
3 years ago
How to find the hybridization?
olganol [36]
CH3 is a methyl radical, which is formed by removing the hydrogen atom from methane, so the hybridization is SP^3
5 0
2 years ago
A piece of metal with a mass of 611 g is placed into a graduated cylinder that contains 25.1 ml of water, raising the water leve
jeka94

Mass of metal piece is 611 g and volume of graduated cylinder is 25.1 mL. When metal piece is placed in the graduated cylinder water level increases to 56.7 mL. The increase in volume is due to volume of metal piece that gets added to the volume of water.

Thus, volume of metal piece can be calculated by subtracting initial volume from the final one.

V_{metal}=V_{final}-V_{initial}=(56.7-25.1)mL=31.6 mL

Thus, volume of metal piece will be 31.6 mL. The mass of metal piece is given 611 g, density of metal can be calculated as follows:

d=\frac{m}{V}=\frac{611 g}{31.6 mL}=19.33 g/mL

Therefore, density of metal is 19.33 g/mL.

3 0
3 years ago
Which of the following is NOT a characteristic of a compound?
MissTica

Answer:

I think it's D

sorry if I'm wrong.

Explanation:

4 0
3 years ago
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