Answer:
C
Step-by-step explanation:
In general for arithmetic sequences, recursive formulas are of the form
aₙ = aₙ₋₁ + d,
and the explicit formula (like tₙ in your problem), are of the form
aₙ = a₁ + (n - 1)d,
where d is the common difference. So converting between the two of these isn't so bad. In this case, your problem wants you to have an idea of what t₁ is (well, every answer says it's -5, so there you are) and what tₙ₊₁ is. Using the formulas above and your given tₙ = -5 + (n - 1)78, we can see that the common difference is 78, so no matter what we get ourselves into, the constant being added on at the end should be 78. That automatically throws out answer choice D.
But to narrow it down between the rest of them, you want to use the general form for the recursive formula and substitute (n + 1) for every instance of n. This will let you find tₙ₊₁ to match the requirements of your answer choices. So
tₙ₊₁ = t₍ₙ₊₁₎₋₁ + d ... Simplify the subscript
tₙ₊₁ = tₙ + d
Therefore, your formula for tₙ₊₁ = tₙ + 78, which is answer choice C.
Answer:
-7, -8 , -9 and -10 are such four integers.
Step-by-step explanation:
Let the first integer = k
So, the next three consecutive integers are ( k+1), ((k + 1) + 1) and (((k + 1) + 1) +1)
or, k , (k +1), (k +2) and (k +3) are four consecutive integers.
Now, their sum is -34.
⇒k + (k +1) + (k +2) + (k +3) = -34
or, 4k + 6 = -34
or, 4k = - 34 - 6 = -40
⇒ k = -40/ 4 = -10
Hence, the first integer k = -10
The next integer = k + 1 = -10 + 1 = -9
Similarly next two integers are -8 and - 7.
So -7, -8 , -9 and -10 are such four integers.
Answer:
h=32 cm
Step-by-step explanation:
12*2=24
+8=32
Answer:
x=28
Step-by-step explanation:
6(x+2)=180 Step 1: Write equation
6x+12=180 step 2: Expand the equation
6x=168 Step 3: Do 180-12 first
x=28 Step 4: Divide by 6 answer you got in Step 3
Step 5: replace 28 with x to see if it's correct 6(28+2)= 180
Put comment if answer is wrong and i will change my answer soon as possible
I hope this helps
In the standard form of quadratic
the discriminant is
In your quadratic, a = 1, b = -9 and c = -10
Now you need to plug these values into the expression for the discriminant.
