((2t+10) / 2) + ((3t-15) / 2) + (3s) = 180
((2t+10) / 2) + ((3t-15) / 2) + (4r) = 180
((2t+10) / 2) + ((3t-15) / 2) + (3s) = ((2t+10) / 2) + ((3t-15) / 2) + (4r)
(2t+10) = (3t-15) t=25
2*25+10= 60 , 3*25-15=60
60+60= 120 , This rectangle has a total of 360 degrees
360 - 120 = 240
240/2 =120
120/ 4 = 30 , 120/3 = 40
r=30 s=40
Answer:
Answer d)
,
, and 
Step-by-step explanation:
Notice that there are basically two right angle triangles to examine: a smaller one in size on the right and a larger one on the left, and both share side "b".
So we proceed to find the value of "b" by noticing that it the side "opposite side to angle 60 degrees" in the triangle of the right (the one with hypotenuse = 10). So we can use the sine function to find its value:

where we use the fact that the sine of 60 degrees can be written as: 
We can also find the value of "d" in that same small triangle, using the cosine function of 60 degrees:

In order to find the value of side "a", we use the right angle triangle on the left, noticing that "a" s the hypotenuse of that triangle, and our (now known) side "b" is the opposite to the 30 degree angle. We use here the definition of sine of an angle as the quotient between the opposite side and the hypotenuse:

where we used the value of the sine function of 30 degrees as one half: 
Finally, we can find the value of the fourth unknown: "c", by using the cos of 30 degrees and the now known value of the hypotenuse in that left triangle:

Therefore, our answer agrees with the values shown in option d)
Answer:
the locus is the perpendicular bisector of the segment
Step-by-step explanation:
The points equidistant from A and B lie on the line that is the perpendicular bisector of segment AB.
_____
<em>Comment on this geometry</em>
You take advantage of this fact when you construct a circle through 3 points. You construct the perpendicular bisectors of segments between pairs of the points, and locate the center of your circle at their intersection.
Answer:
The answer is 5 1/3 or five one thirds
Answer:
c. [1.771;4.245] feet
Step-by-step explanation:
Hello!
The variable of interest is
X: height of a student at UH
X~N(μ;σ²)
You have to estimate the population standard deviation using a 95% confidence interval.
The statistic to use for the interval is a student Chi-Square with n-1 degrees of freedom. First you have to calculate the CI for the population variance:
![[\frac{(n-1)S^2}{X^2_{n-1;1-\alpha /2}} ;\frac{(n-1)S^2}{X^2_{n-1;\alpha /2}} ]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%28n-1%29S%5E2%7D%7BX%5E2_%7Bn-1%3B1-%5Calpha%20%2F2%7D%7D%20%3B%5Cfrac%7B%28n-1%29S%5E2%7D%7BX%5E2_%7Bn-1%3B%5Calpha%20%2F2%7D%7D%20%5D)


n=12
S= 2.5
![[\frac{11*6.25}{21.920} ;\frac{11*6.25}{3.816}} ]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B11%2A6.25%7D%7B21.920%7D%20%3B%5Cfrac%7B11%2A6.25%7D%7B3.816%7D%7D%20%5D)
[3.136; 18.016] feet²
Then you calculate the square root of both limits to get the CI for the population standard deviation:
[√3.136; √18.016]
[1.771;4.245] feet
I hope this helps!