The entropy change, so the appropriate sign is negative. -286.23 J/K (decrease in entropy) Non-spontaneous process.
Entropy is a systematic idea in addition to measurable physical belongings that is most normally associated with a country of ailment, randomness, or uncertainty.
A result of entropy is that certain processes are irreversible or impossible, apart from the requirement of now not violating the conservation of electricity, the latter being expressed inside the first regulation of thermodynamics. Entropy is valuable to the second regulation of thermodynamics.
ENTROPY CHANGE = ENTROPY OF PRODUCT - ENTROPY OF REACTANT
ΔS = ΣΔSf(product) - ΣΔSf(reactant)
1. At STP
[2ΔSf(HNO3 (aq)) + 1ΔSf(NO (g))] - [3ΔSf(NO2 (g)) + 1ΔSf(H2O (ℓ))]
ΔSf(HNO3 (aq) = 146.44 J/K
ΔSf(NO (g) = 210.65 J/K
ΔSf(NO2 (g) = 239.95 J/K
ΔSf(H2O (ℓ) = 69.91 J/K
2(146.44) + 1(210.65)] - [3(239.95) + 1(69.91)] = -286.23 J/K
-286.23 J/K (decrease in entropy)
Non-spontaneous process.
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Answer: the percentage composition of Hydrogen is 18%
Explanation:Please see attachment for explanation
Answer:
Barium carbonate powder is stirred add pulp in the entry, the vitriol that the adds solubility then reaction that makes the transition is filtered and is obtained the barium sulfate filter cake and liquid after the transition.
Answer:
The molarity of this solution is 14.82 mol/dm3 or 14.82 mol/L
Explanation:
- Molarity is the number of mole present in 1 Litre of solution. Molarity of a solution is a term referred to as concentration of a solution. The unit of Molarity is Mol/dm3 or Mol/L.
- let us make an assumption that the volume of the ammonia solution is 1L or 1dm3. Also, 1L = 1000 mL.
Step 1: calculate the mass of the solution
Density = 0.90g/ml (from the question)
Density = mass/ volume
Therefore Mass = density x volume
= 0.90g/ml x 1000ml
mass = 900 g
Step 2: calculate the mass of NH3 present in the solution
Since the concentrated aqueous of ammonia is 28%, It signifies that 1000ml of the solution contains 28% Ammonia
Recall from the above calculation that the mass of 1000 ml of solution is 900 g.
Therefore the mass of ammonia will be 28% of 900 g
mass of NH3 = 0.28 x 900 g
= 252 g
Step 3: calculate the number of mole of NH3
mole = mass/ molar mass
molar mass of NH3 = 17 g/mol
Therefore mole of NH3 = 252/17
= 14.82 mol
Step 4: Calculate Molarity
Molarity = number of moles/ volume of solution in Litre (L)
Molarity = 14.82 / 1
Molarity = 14.82 mol/L