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Amiraneli [1.4K]
3 years ago
10

The alcohol product contains two different types of hydroxyl groups. Why does the polymer-supported reaction with methanol conve

rt only one of the hydroxyl groups to an ether group but not the other
Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
7 0

Answer:

The other may not be free.

Explanation:

In the polymer-supported reaction with methanol, the reaction will undergo at one hydroxyl group because others may not be free due to bonding with other molecules. The hydroxyl groups could be bonded with the polymer with the help of hydrogen bonding of molecules. The hydroxyl group has to be bonded to only the compatible molecules and free molecules.

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The number of electrons in n=1 and n=2 shells of aluminum are
harina [27]

Answer:

n=1 holds two electrons and n=2 holds eight electrons.

Explanation:

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In this case, since the atomic number of aluminum is 13, its electron configuration is:

Al^{13}: 1s^2,2s^2,2p^6,3s^2,3p^1

In such a way, we can see that the level n=1 is filled with two electrons since the subshell s is able to hold two electrons and the level n=2 is also filled but with eight electrons as s holds two whereas p holds 6. Moreover, n=3 is holding three electrons.

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A block of magnesium has a mass of 14.3 g and a volume of 8.46 cm3. What is the density of
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Density is mass over volume, so:
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Estimate the air pressure at an altitude of 5km
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How many millimeters are equal to 0.399195L
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3 years ago
If 16.9 kg of Al2O3(s), 57.4 kg of NaOH(l), and 57.4 kg of HF(g) react completely, how many kilograms of cryolite will be produc
hodyreva [135]

Answer: 69.72 kg of cryolite will be produced.

Explanation:

The balanced chemical equation is:

Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

moles of Al_2O_3 = \frac{16.9\times 1000g}{102g/mol}=165.7moles

moles of NaOH = \frac{57.4\times 1000g}{40g/mol}=1435moles

moles of HF = \frac{57.4\times 1000g}{20g/mol}=2870moles

As 1 mole of Al_2O_3 reacts with 6 moles of NaOH

166 moles of  Al_2O_3 reacts with = \frac{6}{1}\times 166=996 moles of NaOH

As 1 mole of Al_2O_3 reacts with 12 moles of HF

166 moles of  Al_2O_3 reacts with = \frac{12}{1}\times 166=1992 moles of HF

Thus Al_2O_3 is the limiting reagent.

As 1 mole of Al_2O_3 produces = 2 moles of cryolite

166 moles of  Al_2O_3 reacts with = \frac{2}{1}\times 166=332 moles of cryolite

Mass of cryolite (Na_3AlF_6) = moles\times {\text {molar mass}}=332mol\times 210g/mol=69720g=69.72kg

Thus 69.72 kg of cryolite will be produced.

8 0
3 years ago
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