Answer:
0.165
Explanation:
Feel free to let me know if this is wrong because I have seen the question before but cannot really remember!
Answer: Thus the mass, in grams, of 27 moles of smooth muscle myosin is 12960000 grams
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass, occupies 22.4 L at STP contains avogadro's number of particles.
Molecular mass of protein = 480,000 g/mol
Thus 1 mole of protein weighs = 480,000 g
So 27 moles of protein weighs =
Thus the mass, in grams, of 27 moles of smooth muscle myosin is 12960000 grams
Answer:
⇒ n = 2.4088 × 10²⁴
- So, the no of atoms in 4 moles of helium is 2.4088 × 10²⁴.
Explanation:
Get on mathpapa is shows you the answer and how to explain it
Answer:
The balanced equation is given below:
4Cr + 3O₂ —> 2Cr₂O₃
Explanation:
From the question given above the following equation was obtained
4Cr + 3O₂ —> Cr₂O₃
The equation can be balance as illustrated below:
4Cr + 3O₂ —> Cr₂O₃
There are 4 atoms of Cr on the left side and 2 atoms on the right side. It can be balance by writing 2 before Cr₂O₃ as shown below:
4Cr + 3O₂ —> 2Cr₂O₃
Now the equation is balanced.