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3 years ago

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Which is a characteristic of the image formed between F and the center of the lens?

1 answer:

m_a_m_a [10]3 years ago

3 0

Answer: The image is upright

Explanation:

The lens shown in the diagram is concave lens. It is a diverging lens which means that the light rays which fall from the object onto the lens diverge.

Here, the object is kept between focus and center of lens. The image would form between focus and center of the lens at the same side of the object. The image would virtual, diminished and upright. Thus, the correct option is: The image is upright.

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prohojiy [21]

Answer:

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3 years ago

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A long uniform board weighs 52.8 N (10.6 lbs) rests on a support at its mid point. Two children weighing 206.0 N (41.2 lbs) and

balandron [24]

The upward force exerted on the board by the support is mathematically given as

Fu= 764.8 N

<h3>What is the upward force exerted on the board by the support?</h3>

Generally, the equation for is mathematically given as

Considering that the Net Force on the system is null

The weight of the children plus the weight of the board equals the upward force imposed on the support.

The upward force

Fu= 440 + 272 + 52.8 N

Fu= 764.8 N

In conclusion, he upward force exerted on the board by the support

Fu= 764.8 N

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2 years ago

A conservative force on a particle moving along the x axis is given by F = (3x^2-2x)i. Which of the following is a potential tha

ANTONII [103]

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2 years ago

When we do dimensional analysis, we do something analogous to stoichiometry, but with multiplying instead of adding. Consider th

Ksivusya [100]

Answer:

The dimension is $D = L ^{2} T^{-1}$

Explanation:

From the question we are told that

$J = -D \frac{dn}{dx}$

Here $[J] = \frac{1}{L^2 T}$

$[n] =\frac{1}{L^3}$

$[x] = L$

So

$\frac{1}{L^2 T} = -D \frac{d(\frac{1}{L^3})}{d[L]}$

Given that the dimension represent the unites of n and x then the differential will not effect on them

So

$\frac{1}{L^2 T} = -D \frac{(\frac{1}{L^3})}{[L]}$

=> $D = \frac{L^{-2} T^{-1} * L }{L^{-3}}$

=> $D = L ^{2} T^{-1}$

5 0

3 years ago

The radar system of a navy cruiser transmits at a wavelength of 1.4 cm, from a circular antenna with a diameter of 2.7 m. At a r

Goshia [24]

Answer:

Distance will be 49.34 m

Explanation:

We have given wavelength $\lambda =1.4cm =0.014m$

Diameter of the antenna d = 2.7 m

Range L = 7.8 km = 7800 m

We have to find the smallest distance hat two speedboats can be from each other and still be resolved as two separate objects D

We know that distance is given by $D=\frac{L1.22\lambda }{d}=\frac{7800\times 1.22\times 0.014}{2.7}=49.3422m$

So distance D will be 49.34 m

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3 years ago