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klio [65]
2 years ago
6

Colorful light emissions are applicable to everyday life. where else have you observed colorful light emissions? are these light

emission applications related? explain.
Physics
1 answer:
ra1l [238]2 years ago
6 0
<span>Fireworks are a great example of colorful light emissions. When the firework is ignited, it causes light to pass through different metal salts (calcium chloride, sodium nitrate, etc), creating the color of red, blue, white and green.</span>
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What energy powers the star throughout its life?
aleksley [76]
<span>It is called Nuclear fusion. Stars are controlled by atomic combination in their centers, generally changing over hydrogen into helium. The generation of new components by means of atomic responses is called nucleosynthesis. A star's mass figures out what another kind of nucleosynthesis happens in its center.</span>
3 0
3 years ago
A car is travelling to the right with a speed of 40 m/s when the driver slams on the brakes. The car skids for 4 s with constant
vazorg [7]

Answer:

10m/s^2

Explanation:

Given data

velocity= 40m/s

time= 4 seconds

Acceleration a =????

We know that

a= velocity/time

substitute

a=40/4

a= 10m/s^2

Hence the acceleration will be 10m/s^2

3 0
2 years ago
Find the following answer based on the image.
saul85 [17]

<u>We are given:</u>

Mass of Neptune = 1.03 * 10²⁶ kg

Distance from the center of Neptune (r) = 2.27 * 10⁷

now, computing the value of the acceleration due to gravity (g)

<u>Finding g:</u>

We know the formula:

g = G(mass of planet) / (r)²

g = [6.67 * 10⁻¹¹ * 1.03*10²⁶] / (2.27*10⁷)                      [since G is 6.67*10⁻¹¹]

g = (6.87 * 10¹⁵) / (5.15 * 10¹⁴)

which can be rewritten as:

g = (6.87 * 10¹⁵ * 10⁻¹⁴) / 5.15

g = (6.87 * 10¹⁵⁻¹⁴) / 5.15

g = (6.87/5.15) * 10

g = 1.34 * 10

g = 13.4 m/s² <em>(approx)</em>

5 0
3 years ago
A 60 kilogram student jumps down from a laboratory counter. At the instant he lands on the floor hus speed is 3 meters per secon
erastovalidia [21]

As per Newton's law rate of change in momentum is net force

so we can write it as

F = \frac{dP}{dt}

F = \frac{m(v_f - v_i)}{\Delta t}

now we know that

m = 60 kg

v_f = 3 m/s

v_i = 0

\Delta t= 0.2 s

from above equation

F = \frac{60(3 - 0)}{0.2} = 900 N

so he will experience 900 N force in above case

5 0
2 years ago
Help. I need to find the degree using the sine law.
Marina CMI [18]
Use pythagorean theorem
a ^{2}  + b {}^{2}  = c {}^{2}
to find the opposite side, which is 7.3

so then you can just use inverse sinA=7.3/10 which equals 46.9 degrees
4 0
3 years ago
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