Answer:
See Below.
Explanation:
Quadratic Form:
Quadratic Formula:
Based on the information given from the question, we can deduce:
a = 1
b = 6
c = -5
Now we can substitute all these values into the formula to find x.
C=5n+125
Domain :n=0,1,2,3...
Range:C ≥125
Answer: 3t²(2st⁷ - s⁶ - 2t⁵)
<u>Step-by-step explanation:</u>
5s⁶t² + 6st⁹ - 8s⁶t² - 6t⁷ <em>5s⁶t² and - 8s⁶t² are like terms which = -3s⁶t² when combined</em>
= 6st⁹ - 3s⁶t² - 6t⁷ <em>next, factor out the GCF of 3t²</em>
= 3t²(2st⁷ - s⁶ - 2t⁵)
Step-by-step explanation:
let's look at the last line :
x³ + 8x - 3 = Ax³ +5Ax + Bx² + 5B + Cx + D
since we find A, B, C, and D by simply comparing the factors of the various terms in x (or constants) in both sides of the equation, we need to combine a few terms on the right hand side (so that we have one term per x exponent grade).
x³ + 8x - 3 = Ax³ + (5A + C)x + Bx² + (5B + D)
by comparing now both sides, to make both sides truly equal, the factors have to be equal.
A = 1 (the same as for x³ on the left hand side).
B = 0 (a we have no x² on the left side).
5A + C = 8 (a 8 is the factor of x in the left side).
5×1 + C = 8
5 + C = 8
C = 3
5B + D = -3 (as the constant term is -3 on the left side).
5×0 + D = -3
D = -3
so, the 4th answer option is correct.
