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2 years ago

two sides of a triangle measures 20 centimeters and 30 centimeters which of the following could be the measure of the third side

1 answer:

6 0

To find the third side of a triangle (there are two answers you could get), you need to use the Pythagorean formula: a^2+b^2=c^2. First answer, 20^2+30^2=c^2. Solve for c. c=36.06. The second answer, 20^2+b^2=30^2. Solve for b. b=26.36.

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Ratna , who is in Mumbai , telephones her brother Ravi in Ahmedabad and speaks for 89 seconds . She is charged Rs 1.20 for every

blondinia [14]

Answer:

16.40

Step-by-step explanation:

3 min-> 180 s

180÷16≈11

11+1=12

12x1.20=14.40

14.40 + 2 = 16.40

7 0

2 years ago

If a jacket was purchased at £75 and had 20% off, what would the price be?

IceJOKER [234]

20% of 75 = 15

75 - 15 = £60

It should be c) £60

8 0

2 years ago

Instructions

PilotLPTM [1.2K]

I chose a box of cereal-------> rectangular prism
see the attached figure

Part 1)List the dimensions of your box. Be sure to include the units (in, cm, ft, etc.).
Length: 20 cm
Width: 8 cm
Height: 32 cm

Part 2).
Describe the shape of the cross-section when the box is cut parallel to the base

the shape of the cross-section would be a rectangle of dimensions
20 cm x 8 cm

Part 3)
What is the surface area of the box?

surface area=2*area of the base+perimeter of the base*height

area of the base=20*8=160 cm²

perimeter of the base=2*[20+8]-----> 56 cm
height=32 cm

surface area=2*160+56*32------> 2,112 cm²

the answer part 3) is
2,112 cm²

Part 4)
What is the surface area of the box if it is scaled up by a factor of 10?

we know that
surface area of the larger box=[scale factor]²*surface area original box

scale factor=10
surface area original box=2,112 cm²
so
surface area of the larger box=10²*2,112-----> 211,200 cm²

the answer part 4) is
211,200 cm²

Part 5)
What is the volume of the box?

volume of the box=L*W*H-----> 20*8*32------> 5,120 cm³

the answer Part 5) is
5,120 cm³

Part 6)
What is the volume of the box if it is scaled down by a factor of 1/10

we know that
volume of the smaller box=[scale factor]³*volume original box
scale factor=1/10
volume original box=5,120 cm³
so
volume of the smaller box=[1/10]³*5,120-----> 5.12 cm³

the answer part 6) is
5.12 cm³

6 0

2 years ago

Quadrilateral PEST has vertices (-1, -5), (8, 2), (11, 13), and (2, 6), respectively. Classify the quadrilateral as a square, rh

Alchen [17]

Answer:

The figure PEST is a rhombus

Step-by-step explanation:

* Lets talk about the difference between all these shapes

- At first to prove the shape is a parallelogram you must have one

of these conditions

# Each two opposite sides are parallel OR

# Each two opposite sides are equal in length OR

# Its two diagonals bisect each other

- After that to prove the parallelogram is:

* A rectangle you must have one of these conditions

# Two adjacent sides are perpendicular to each other OR

# Its two diagonals are equal in length

* A rhombus you must have one of these conditions

# Two adjacent sides are equal in length OR

# Its two diagonals perpendicular to each other OR

# Its diagonals bisect its vertices angles

* A square you must have two of these conditions

# Its diagonals are equal and perpendicular OR

# Two adjacent sides are equal and perpendicular

* Now lets solve the problem

∵ The vertices of the quadrilateral PEST are

P (-1 , -5) , E (8 , 2) , S (11 , 13) , T (2 , 6)

- Lets find the slope from each two points using this rule :

m = (y2 - y1)/(x2 - x1), where m is the slope and (x1 , y1) , (x2 , y2)

are two points on the line

- Let (x1 , y1) is (-1 , -5) and (x2 , y2) is (8 , 2)

∴ m of PE = (2 - -5)/(8 - -1) = 7/9

- Let (x1 , y1) is (8 , 2) and (x2 , y2) is (11 , 13)

∴ m of ES = (13 - 2)/(11 - 8) = 11/3

- Let (x1 , y1) is (11 , 13) and (x2 , y2) is (2 , 6)

∴ m of ST = (6 - 13)/(2 - 11) = -7/-9 = 7/9

- Let (x1 , y1) is (2 , 6) and (x2 , y2) is (-1 , -5)

∴ m of TP = (-5 - 6)/(-1 - 2) = -11/-3 = 11/3

∵ m PE = m ST = 7/9

∴ PE // ST ⇒ opposite sides

∵ m ES = m TP = 11/3

∴ ES // TP ⇒ opposite sides

- Each two opposite sides are parallel

∴ PEST is a parallelogram

- Lets check if the parallelogram can be rectangle or rhombus or

square by one of the condition above

∵ If two line perpendicular , then the product of their slops = -1

- Lets check the slopes of two adjacent sides (PE an ES)

∵ m PE = 7/9

∵ m ES = 11/3

∵ m PE × m ES = 7/9 × 11/3 = 77/27 ≠ -1

∴ PE and ES are not perpendicular

∴ PEST not a rectangle or a square (the sides of the rectangle and

the square are perpendicular to each other)

- Now lets check the length of two adjacent side by using the rule

of distance between two points (x1 , y1) and (x2 , y2)

d = √[(x2 - x1)² + (y2 - y1)²]

- Let (x1 , y1) is (-1 , -5) and (x2 , y2) is (8 , 2)

∴ PE = √[(8 - -1)² + (2 - -5)²] = √[9² + 7²] = √[81 + 49] = √130 units

- Let (x1 , y1) is (8 , 2) and (x2 , y2) is (11 , 13)

∴ ES = √[(11 - 8)² + (13 - 2)²] = √[3² + 11²] = √[9 + 121] = √130 units

∴ PE = ES ⇒ two adjacent sides in parallelogram

∴ The four sides are equal

* The figure PEST is a rhombus

4 0

2 years ago

HELPPP MEE BEST ANSWER GET THE BRAINLIEST!!

Zielflug [23.3K]

1/2= /360 is the correct answer choice

4 0

2 years ago

Read 2 more answers