Answer:
e. 3.08 x 10⁻² mol of ions.
Explanation:
- Every 1.0 mole of any compound contains Avogadro's number of molecules (6.022 x 10²³).
- We can get the no. of moles of NiCl₂ using cross multiplication:
1.0 mol NiCl₂ contains → 6.022 x 10²³ molecules.
??? mol NiCl₂ contains → 6.188 x 10²¹ molecules.
∴ The no. of moles of NiCl₂ = (1.0 mol)(6.188 x 10²¹ molecules)/(6.022 x 10²³ molecules) = 1.028 x 10⁻² mol.
- NiCl₂ is ionized according to the equation:
NiCl₂ → Ni²⁺ + 2Cl⁻.
Which means that every 1.0 mol of NiCl₂ is ionized to produce 3.0 moles (1.0 mol of Ni²⁺ and 2 moles of Cl⁻).
<em>∴ The total moles of ions are released</em> = 3 x 1.028 x 10⁻² mol = <em>3.083 x 10⁻² mol of ions.</em>
Answer:
Just use a text book.. So that you get the concept
Answer: [Kr] 5s1 4d10 silver
[Xe] 6s2 4f14 5d7 Iridium
[Ar] 4s2 3d10 4p4 selenium
[Kr] 5s1 4d4 niobium
[Xe] 6s1 4f14 5d10 gold
[Kr] 5s2 4d10 5p4 tellurium
Explanation:
Selenium and tellurium will have the same properties because they both belong to group 16 in the periodic table.
Silver and gold will have the same properties because they both belong the group 11 in the periodic table.
Elements having the same outermost shell configuration show similar properties since chemical reactions occur by loss or gain of electrons. This loss or gain is determined by the number of electrons occupying the outermost shell. Elements in the same group have the same outermost shell electron configuration and similar properties.
There is fr-218
hope this did the job, have a nice rest of your day!!
