Answer:
[Ni²⁺] = 1.33 M
Explanation:
To do this, we need to use the Nernst equation which (in standard conditions of temperature)
E = E° - RT/nF lnQ
However R and F are constant, and the reaction is taking place in 25 °C so we can assume the nernst equation like this:
E = E° - 0.05916/n logQ
As the nickel is in the cathode, this means that this element is being reducted while Cadmium is being oxidized, therefore the REDOX reaction would be:
Cd(s) + Ni²⁺(aq) --------> Cd²⁺(aq) + Ni(s)
With this, Q:
Q = [Cd²⁺] / [Ni²⁺]
Now, we need to know the value of the standard reduction potentials, which can be calculated with the semi equations of reduction and oxidation:
Cd(s) ------------> Cd²⁺ + 2e⁻ E°₁ = 0.40 V
Ni²⁺ + 2e⁻ -------------> Ni(s) E°₂ = -0.25 V
E° = E°₁ + E°₂
E° = 0.40 - 0.25 = 0.15 V
Now that we have all the data, we can solve for the [Ni²⁺]:
0.133 = 0.15 - 0.05916/2 log(5/[Ni²⁺])
0.133 - 0.15 = -0.05916/2 log(5/[Ni²⁺])
-0.017 = -0.02958 log(5/[Ni²⁺])
-0.017/-0.02958 = log(5/[Ni²⁺])
0.5747 = log(5/[Ni²⁺])
10^(0.5747) = 5/[Ni²⁺]
[Ni²⁺] = 5/3.7558
<h2>
[Ni²⁺] = 1.33 M</h2>
The volume occupied by the gas in the container is 1 m³
Boyles law applies
P₁ V₁ = P₂ V₂
Where P₁ = 200kpa
P₂ = 300kpa
if its initial volume is 1.5
then,
P₁ V₁ = P₂ V₂
200 × 1.5 = 300 × V₂
V₂ = 200 × 1.5 / 300
= 1 m³
Hence the volume occupied by the gas container is 1 m³
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The normality of the H₂SO₄ that reacted with 25cc of 5 % NaOH solution is 1.1 N.
<h3>What is the molarity of 5% NaOH?</h3>
The molarity of 5% NaOH is 1.32 M
25 cc of NaOH neutralized 30cc of H₂SO₄ solution.
Equation of reaction is given below:
- 2 NaOH + H₂SO₄ ---> Na₂SO₄ + 2 H₂O
Molarity of H₂SO₄ = 1.32 x 1 x 25/(30 x 2) = 0.55 M
- Normality = Molarity × moles of H⁺ ions per mole of acid
moles of H⁺ ions per mole of H₂SO₄ = 2
Normality of H₂SO₄ = 0.55 x 2 = 1.1 N
In conclusion, the normality of an acid is determined from the molarity and the moles of H⁺ ions per mole of acid.
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Answer:
What type of bonds are shown in this diagram?
A: covalent bonds
B: ionic bonds
C: hydrogen bonds
D: metallic bonds
(answer) metallic bonds
In what type of bonds do atoms join together because their opposite charges attract each other?
A: metallic bonds and covalent bonds
B: metallic bonds and ionic bonds
C: ionic bonds and covalent bonds
D: ionic bonds and hydrogen bonds
(answer) ionic bonds and hydrogen bonds
What types of bonds are shown in this diagram?
A: covalent bonds
B: ionic bonds
C: hydrogen bonds
D: metallic bonds
(answer) hydrogen bonds
Which statement best describes the types of bonds shown in the diagram?
A: an ionic bond; the hydrogen chloride molecule has an electrical charge
B: an ionic bond; a hydrogen ion is bonding with a chlorine atom
C: a covalent bond; the hydrogen atom’s two electrons are being shared with the chlorine atom
D: a covalent bond; the hydrogen atom’s single electron is being shared with the chlorine atom
(answer) a covalent bond; the hydrogen atom’s single electron is being shared with the chlorine atom
Which of the following bonds is the strongest?
A: hydrogen bonds
B: metallic bonds
C: valence bonds
D: covalent bonds
(answer)
Explanation:
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