Twice the product of 3and a number exceeds the sum of the number and 80 by 10.what is the number?

1 answer:

6 0

First, create an equation with the criteria given.

If we let x be your number,
$2(3x) = 80 + x + 10$
( $2(3x)$ is twice the product of 3 and x, and if it exceeds $x+80$ by 10, then we add 10 to $x+80$ to make the two sides of the equation equal.)

Now, solve for $x$ .

$6x=90+x \\ 5x=90 \\ x=18$

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See proof below

Step-by-step explanation:

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