Answer: 2.7 m/s
Explanation:
Given the following :
Period (T) = 8.2 seconds
Radius = 3.5 m
The tangential speed is given as:
V = Radius × ω
ω = angular speed = (2 × pi) / T
ω = (2 × 22/7) / 8.2
ω = 6.2857142 / 8.2
ω = 0.7665505
Therefore, tangential speed (V) equals;
r × ω
3.5 × 0.7665505 = 2.6829268 m/s
2.7 m/s
Answer:
61.0168 g/mol Explanation:
(a) is a decomposition reaction
Answer:
A) How much work does the Pepsi do on the bullet = 0.0625J
B) At what velocity does the Pepsi hit the floor = 7.67m/s
Explanation:
- Given mass of bullet = 5g
- initial velocity = 500 m/sec
From work done = Force X Distance
Workdone ; m(v - u )/t
A) The work done by the Pepsi is equal to the change in kinetic energy while in the Pepsi:
- but The work done by the container wall on the bullet is equal to the change in kinetic energy on either side of the wall: W = change in kinetic energy = 1/2 mv²
= 1/2 X 0.005 x 500² - 1/2 X 0.055 x 5²
= 624.94J
- Therefore ; The work done by the Pepsi is equal to the change in kinetic energy while in the Pepsi = W = change in KE = 0.0625 - 0 = 0.0625J
B) At what velocity does the Pepsi hit the floor?
- From conservation of energy principle; PE = KE
