Answer:
If an object has a net force acting on it, it will accelerate. The object will speed up, slow down or change direction. An unbalanced force (net force) acting on an object changes its speed and/or direction of motion. An unbalanced force is an unopposed force that causes a change in motion.
Explanation:
I hope this helps you out and if your feeling generous plz mark brainliest it helps me a lot thank you:)
Answer:
His average speed is 980 units
To stop instantly, you would need infinite deceleration. This in turn, requires infinite force, as demonstrable with this equation:F=ma<span>So when you hit a wall, you do not instantly stop (e.g. the trunk of the car will still move because the car is getting crushed). In a case of a change in momentum, </span><span><span>m<span>v⃗ </span></span><span>m<span>v→</span></span></span>, we can use the following equation to calculate force:F=p/h<span>However, because the force is nowhere close to infinity, time will never tend to zero either, which means that you cannot come to an instantaneous stop.</span>
Answer:
mass is 6.97 pounds
Explanation:
given data
volume = 3.1 liters
density = 1.020 g/ml = 1.02 kg/l
to find out
How many pounds of blood plasma
solution
we know mass formula from density that is
density = mass / volume
so
mass = density × volume ...............1
so put all value to get mass
mass = 1.02 × 3.1
mass = 3.162 kg
mass = 3.162 × 2.205 pounds
so mass is 6.97 pounds
Answer:
Explanation:
Given
![P_1=150 kPa](https://tex.z-dn.net/?f=P_1%3D150%20kPa)
![T_1=20^{\circ}C](https://tex.z-dn.net/?f=T_1%3D20%5E%7B%5Ccirc%7DC)
![V_1=0.5 m^3](https://tex.z-dn.net/?f=V_1%3D0.5%20m%5E3)
![T_2=140^{\circ}C](https://tex.z-dn.net/?f=T_2%3D140%5E%7B%5Ccirc%7DC)
![P_2=400 kPa](https://tex.z-dn.net/?f=P_2%3D400%20kPa)
R for Helium ![R=2.076](https://tex.z-dn.net/?f=R%3D2.076)
![c_v=3.115 kJ/kg-K](https://tex.z-dn.net/?f=c_v%3D3.115%20kJ%2Fkg-K)
mass of gas ![m=\frac{P_1V_1}{RT_1}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7BP_1V_1%7D%7BRT_1%7D)
![m=\frac{150\times 0.5}{2.076\times 293}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B150%5Ctimes%200.5%7D%7B2.076%5Ctimes%20293%7D)
![m=0.123 kg](https://tex.z-dn.net/?f=m%3D0.123%20kg)
Similarly
can be found
![\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1V_1%7D%7BT_1%7D%3D%5Cfrac%7BP_2V_2%7D%7BT_2%7D)
![V_2=0.264 m^3](https://tex.z-dn.net/?f=V_2%3D0.264%20m%5E3)
Work done ![W=\int_{V_1}^{V_2}PdV](https://tex.z-dn.net/?f=W%3D%5Cint_%7BV_1%7D%5E%7BV_2%7DPdV)
![W=\frac{P_2V_2-P_1V_1}{n-1}](https://tex.z-dn.net/?f=W%3D%5Cfrac%7BP_2V_2-P_1V_1%7D%7Bn-1%7D)
![W=\frac{mR(T_2_T_1)}{n-1}](https://tex.z-dn.net/?f=W%3D%5Cfrac%7BmR%28T_2_T_1%29%7D%7Bn-1%7D)
Since it is a polytropic Process
therefore ![PV^n=c](https://tex.z-dn.net/?f=PV%5En%3Dc)
![P_1V_1^n=P_2V_2^n](https://tex.z-dn.net/?f=P_1V_1%5En%3DP_2V_2%5En)
![(\frac{V_1}{V_2})^n=\frac{P_2}{P_1}](https://tex.z-dn.net/?f=%28%5Cfrac%7BV_1%7D%7BV_2%7D%29%5En%3D%5Cfrac%7BP_2%7D%7BP_1%7D)
![(\frac{0.5}{0.264})^n=\frac{400}{150}](https://tex.z-dn.net/?f=%28%5Cfrac%7B0.5%7D%7B0.264%7D%29%5En%3D%5Cfrac%7B400%7D%7B150%7D)
![n=\frac{\ln 2.66}{\ln 1.893}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B%5Cln%202.66%7D%7B%5Cln%201.893%7D)
![n=1.533](https://tex.z-dn.net/?f=n%3D1.533)
![W=\frac{0.123\times 2.076(140-20)}{1.533-1}](https://tex.z-dn.net/?f=W%3D%5Cfrac%7B0.123%5Ctimes%202.076%28140-20%29%7D%7B1.533-1%7D)
From Energy balance
Neglecting kinetic and Potential Energy change
![Q_{in}+W_{in}=change\ in\ Internal\ Energy](https://tex.z-dn.net/?f=Q_%7Bin%7D%2BW_%7Bin%7D%3Dchange%5C%20in%5C%20Internal%5C%20Energy)
Change in Internal Energy ![\Delta U=u_2-u_1](https://tex.z-dn.net/?f=%5CDelta%20U%3Du_2-u_1)
![\Delta U=mc_v(T_2-T_1)](https://tex.z-dn.net/?f=%5CDelta%20U%3Dmc_v%28T_2-T_1%29)
![\Delta U=0.123\times 3.115(140-20)](https://tex.z-dn.net/?f=%5CDelta%20U%3D0.123%5Ctimes%203.115%28140-20%29)
![\Delta U=45.977 kJ](https://tex.z-dn.net/?f=%5CDelta%20U%3D45.977%20kJ)
![Q_{in}+57.48=45.977](https://tex.z-dn.net/?f=Q_%7Bin%7D%2B57.48%3D45.977)
i.e. Heat is being removed