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DedPeter [7]
3 years ago
7

In Lesson 20, a magnesium strip was used to ignite the thermite reaction. When magnesium is placed in a flame from a small blow

torch, it burns quite brightly forming magnesium oxide, a salt that contains one magnesium for every oxygen. In the following questions you will be asked to provide some details of the chemical processes involved in a reaction between magnesium and oxygen. How many more electrons does unbound oxygen need to fill its 2nd shell?
Physics
1 answer:
nadezda [96]3 years ago
6 0

Answer:

2 electrons will be needed by unbound oxygen in order to fill its 2nd shell.

Explanation:

The chemical reaction between magnesium and oxygen gives magnesium oxide as a product.The reaction is chemically represented as:

2Mg(s)+O_2(g)\rightarrow 2MgO(s)

Magnesium is a metal of group-2 with 2 valence electrons.It has atomic number of 12.

[Mg]=1s^22s^22p^63s^2

In order to attain noble gas configuration it will loose two electrons.

[Mg]^{2+}=1s^22s^22p^6

Mg\rightarrow Mg^{2+}+2e^-...[1]

Oxygen is a non metal of group-16 with 6 valence electrons..It has atomic number of 8.

[O]=1s^22s^22p^4

In order to attain noble gas configuration it will gain two electrons.

[O]^{2-}=1s^22s^22p^6

O+2e^-\rightarrow O^{2-}..[2]

2 electrons will be needed by unbound oxygen in order to fill its 2nd shell.

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The force between two charges, q, and 92, is F. If the distance between the
Sholpan [36]

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4F

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2 years ago
If a moving car speeds up until it is going twice as fast, how much kinetic energy doe s it have compared with its initial kinet
dezoksy [38]
The kinetic energy of an object of mass m and velocity v is given by
K= \frac{1}{2} mv^2

Let's call v_i the initial speed of the car, so that its initial kinetic energy is
K_i =  \frac{1}{2} mv_i^2
where m is the mass of the car. 

The problem says that the car speeds up until its velocity is twice the original one, so 
v_f = 2 v_i
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6 0
3 years ago
A 10n falling object encounters 4n of air resistance. what is the net force on the object?
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5 0
3 years ago
You throw a ball straight up. You are extra strong feeling today. It takes 11 seconds for the ball to come back down.
ollegr [7]

Answer:

A. 148.23 m

B. 2.75 m/s

Explanation:

The following data were obtained from the question:

Time of flight (T) = 11 s

Maximum height (h) =?

Initial velocity (u) =?

Next, we shall determine the time taken for the ball to get to the maximum height. This can be obtained as follow:

Time of flight (T) = 11 s

Time (t) to reach the maximum height =.?

T = 2t

11 = 2t

Divide both side by 2

t = 11/2

t = 5.5 s

NOTE: Time to reach the maximum height is the same as the time taken for the ball to fall back to the plane of projection.

A. Determination of the maximum height to which the ball was thrown.

Time (t) to reach maximum height = 5.5 s

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) =?

h = ½gt²

h = ½ × 9.8 × 5.5²

h = 4.9 × 30.25

h = 148.23 m

B. Determination of the initial velocity.

Maximum height (h) reached = 148.23 m

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u) =?

u² = h/2g

u² = 148.23 / (2 × 9.8)

u² = 148.23 / 19.6

Take the square root of both side

u = √(148.23 / 19.6)

u = 2.75 m/s

5 0
2 years ago
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