Answer:
The mantle exists above the crust of the earth
The IRB at the university will decide whether her study meets ethical guidelines before it is initiated. The importance of these codes of conduct is to safeguard research participants, the status of psychology and the researchers or psychologists themselves. Moral issues hardly yield a simple, unequivocal, right or wrong answer. It is consequently often a matter of judgment whether the research is justified or not. For instance, it might be that a study roots psychological or physical uneasiness to participants, maybe they agonize pain or maybe even come to solemn harm.
The addition of vectors and the uniform motion allows to find the answers for the questions about distance and time are:
- The distance to go between airports A and C is 373.6 10³ m
- The time to go from airport A to B is 2117 s
Vectors are quantities that have modulus and direction, so their addition must be done using vector algebra.
In this case the plane flies towards the North a distance of y = 360 10³ m at an average speed of v = 170 m / s, when arriving at airport B it turns towards the East and travels from x = 100 10³ m, until' it the distance reaches the airport C
Let's use the Pythagoras theorem to find the distance traveled
R = Ra x² + y²
R = 10³
R = 373.6 10³ m
They indicate the average speed for which we can use the uniform motion ratio
v = 
t = 
They ask for the time in in from airport A to B, we calculate
t = 360 10 ^ 3/170
t = 2.117 10³ s
In conclusion we use the addition of vectors the uniform motion we can find the answer for the question of distance and time are:
- The distance to go between airports A and C B is 373.6 10³ m
- The time to go from airport A to B is 2117 s
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Answer:
a) 27.2 V
b)27.2 V
Explanation:
Charge of the electron =charge of the proton = q = 1.6 × 10⁻¹⁹ C
Radius = r = 0.53×10⁻¹⁰ m
Electric Potential = V = k q/r
k = 9 ×10⁹ N m²/C² = Coulomb's constant.
V = (9 ×10⁹)(1.6 × 10⁻¹⁹)/( 0.53×10⁻¹⁰) = 27.2 V
b) Potential Energy of the electron = k q × q / r
= [(9 ×10⁹)(1.6 × 10⁻¹⁹)(1.6 × 10⁻¹⁹) / (0.53×10⁻¹⁰)] / (1.6 × 10⁻¹⁹) eV,
since 1 electron volt = (1.6 × 10⁻¹⁹)joules
= 27.2 eV