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2 years ago

An object is accelerating if there is a change in speed and/ or which factor A.Time B.Position C.Direction D.Displacment

Physics

2 answers:

astra-53 [7]2 years ago

5 0

"Acceleration" is a change in speed, or direction of motion, or both.

enot [183]2 years ago

5 0

hey there!!!

I believe the answer is C). Direction. Since when something in speed changes, it can cause the direction to change or position but I would mainly say if there is a change in spped then the dircetion will somehow or somewhat change also.

Hope that helps!!! :)

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A horizontal uniform bar of mass 2.5 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to t

11Alexandr11 [23.1K]

Answer: I am not sure if you wanted me to answer this or not.

Explanation:

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1 year ago

When you throw a ball, the work you do to accelerate it equals the kinetic energy the ball gains. if you do twice as much work w

nata0808 [166]

It doesn't because when u threw it the first time, u notice that the ball eventually came to a stop because of the force that was acting upon it. Although when u throw it harder it will start out faster than the first time u threw it because u put more kinetic energy onto the ball. But the same thing happens with this ball that happened to the second ball, they both have a type of force acting upon them.

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2 years ago

In electromagnetic waves, frequency is inversely proportional to

forsale [732]

Frequency is inversely proportional to wavelength.

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If the wave's speed if c, then f=c/l where l is the wavelength.

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2 years ago

Read 2 more answers

In the late 19th century, great interest was directed toward the study of electrical discharges in gases and the nature of so-ca

svlad2 [7]

Answer:

a) He found the same value of q/m for different cathode materials.

b) y = $- \frac{e}{m}\ \frac{E_o v_o^2 }{2d^2}$ , c) v = $\frac{E_o}{B_o}$

Explanation:

In Thomson's experiments he was able to measure the deflection of the light beam under the effect of the magnetic field and with these results find the e / m relationship, which in all cases is the same, therefore the most important conclusion is that the value e E / m is constant for all materials.

b) In the part of the plates the electrons are accelerated by the electric field,

F = ma

- e E = m a

a = - (e/m) E₀

the distance traveled is

X axis

x = v₀ t

the separation of the plates is x = d

t = vo / d

Y axis

y = v_{oy} t + ½ to t²

y = ½ a t²

y = $- \frac{e}{m}\ \frac{E_o v_o^2 }{2d^2}$

c) In this case there is a magnetic field B₀ and the electrons have no deflection

F = - e E + e v x B

if there is no deviation F = 0

e E = e v B

v = $\frac{E_o}{B_o}$

5 0

2 years ago

(a) Figure 1 shows a mas of 1200 kg hung by a massless cable supported by a counterweight of mass 900 kg. You may assume the gra

Effectus [21]

Answer:

1.43 m/s², 10,300 N

Explanation:

First things first is to draw a picture. Fortunately, one was already provided.

Next, we need to draw a free body diagram for each mass.

The 1200 kg mass has two forces acting on it: tension pulling up and weight pulling down.

Similarly, the 900 kg mass has two forces acting on it: tension pulling up and weight pulling down.

Now we apply Newton's second law. Let's start with the 1200 kg. If we say that up is positive, then:

∑F = ma

T - W = M(-a)

T - Mg = -Ma

Notice that I made the acceleration negative. That's because we know that the heavier mass will be accelerating down.

Now we apply Newton's second law to the 900 kg mass:

∑F = ma

T - W = ma

T - mg = ma

Now we have two equations and two unknowns (T and a). Let's solve for the acceleration first. To do that, let's subtract the two equations so we can eliminate T (if you prefer, you can also use substitution instead):

-mg − (-Mg) = ma − (-Ma)

-mg + Mg = ma + Ma

g (M - m) = a (M + m)

a = g (M - m) / (M + m)

Given that M = 1200 kg, m = 900 kg, and g = 10 m/s²:

a = 10 m/s² (1200 kg - 900 kg) / (1200 kg + 900 kg)

a = 10/7 m/s²

a ≈ 1.43 m/s²

Now let's find the tension by plugging our answer into either of the two equations.

T - mg = ma

T - (900 kg) (10 m/s²) = (900 kg) (10/7 m/s²)

T = 72000/7 N

T ≈ 10,300 N

I'm not sure what rounding rules you need to follow, but hopefully this helps.

3 0

3 years ago