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yawa3891 [41]
3 years ago
5

An object is accelerating if there is a change in speed and/ or which factor A.Time B.Position C.Direction D.Displacment

Physics
2 answers:
astra-53 [7]3 years ago
5 0

"Acceleration" is a change in speed, or direction of motion, or both.

enot [183]3 years ago
5 0

hey there!!!



I believe the answer is C). Direction. Since when something in speed changes, it can cause the direction to change or position but I would mainly say if there is a change in spped then the dircetion will somehow or somewhat change also.





Hope that helps!!! :)

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Order the sequence of ideas that led to Marie Curie’s discovery of radioactive elements. Number the events in chronological orde
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Answer:

2 1 3

Explanation:

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3 years ago
If a trapezoidal channel has side slopes of 1:1, hydraulic depth is 5 feet, the bottom width is 8 feet, flow is 2,312 cubic feet
Evgesh-ka [11]

Answer:

S = \dfrac{1}{2.5}

Explanation:

given,

side slope = 1 : 1

hydraulic depth(y) = 5 ft

bottom width (b)= 8 ft

x = 1

Q = 2,312 ft³/s

n = 0.013

slope of channel = ?

R = \dfrac{A}{P}

R = \dfrac{y(b + xy)}{b+2y\sqrt{1+x^2}}

R = \dfrac{5(8+ 5)}{8+2\times 5\sqrt{1+1^2}}

R = 4.69 m

using manning's equation

Q = \dfrac{1}{n}AR^{2/3} S^{1/2}

2312= \dfrac{1}{0.013}\times (5(8+5))\times 4.69^{2/3} S^{1/2}

2312=14009.37\times S^{1/2}

S = 0.406

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5 0
3 years ago
Suppose a 2.0kg bird is flying at a speed of of 1m/s. It’s kinetic energy would be what?
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As we know that the formula of kinetic energy will be

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7 0
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V125BC [204]

Answer:

2.00 m/s²

Explanation:

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Co-efficient of kinetic friction, \mu_k = 0.3

Now,

The force against the kinetic friction is given as:

f = \mu_k N = u_k Mg

Where,

N = Normal reaction

g= acceleration due to the gravity

Substituting the values in the above equation, we get

f = 0.3\times108\times9.8

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f = 317.52N

Now, the net force on to the metal safe is

F_{Net}= F-f

Substituting the values in the equation we get

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or

F_{Net}= 216.48

also,

 

F_{Net}= M\timesacceleration of the safe

Therefore, the acceleration of the metal safe will be

acceleration of the safe=\frac{F_{Net}}{M}

or

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or

 

acceleration of the safe=2.00 m/s^2

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If a 93000 kg truck collides with a 60 kg car
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