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Tasya [4]
3 years ago
12

A race car starts at rest and speeds up to 40 m/s in a distance of 100 m. Determine the acceleration of the car.

Physics
1 answer:
Finger [1]3 years ago
8 0

Answer:

Acceleration of the car, a=8\ m/s^2

Explanation:

Given that,

Initial speed of the car, u = 0 (at rest)

Final speed of the car, v = 40 m/s

Distance covered, s = 100 m

We need to find the acceleration of the car. It can be calculated using third equation of motion as :

v^2-u^2=2as

a is the acceleration of the car

a=\dfrac{v^2}{2s}

a=\dfrac{(40)^2}{2\times 100}

a=8\ m/s^2

So, the acceleration of the car is 8\ m/s^2. Hence, this is the required solution

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2 years ago
An electron has a constant acceleration of +3.3 m/s2. at a certain instant its velocity is +8.6 m/s. what is its velocity (a) 2.
Citrus2011 [14]
Hello!


The velocity function is:

\mathsf{V = V_0 + at}\\ \\ \mathsf{V = 8.6 +3.3t}


a) 2.3 s earlier, we can make t = -2.3 s, in relation to our initial time:

\mathsf{V = 8.6 + 3.3\cdot(-2.3)}\\ \\ \mathsf{V = 8.8-7.59}\\ \\ \boxed{\mathsf{V = 1.21 \ m/s}}

b) Now we can make t = 2.3 s:

\mathsf{V = 8.6 + 3.3\cdot2.3}\\ \\ \mathsf{V = 8.6 + 7.59}\\ \\ \boxed{\mathsf{V = 15.59 \ m/s}}
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3 years ago
a generator produces a maximum emf of 240 v when rotating at 3.7 rad/s in a magnetic field of 0.200 t. if the coil has 822 loops
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Answer:

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2 years ago
How to do it? Urgent ​
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a)

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F=35N

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