I am confused with this word problem.

Mathematics

1 answer:

bazaltina [42]3 years ago

8 0

Answer:

30pgs=$20

42pgs=$26

Step-by-step explanation:

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Y = 2 - 4x input output

tester [92]

Every function is a rule which tells you how to associate inputs and outputs. The input, also known as independent variable, is often indicated with the letter $x$ , while the output, also known as dependent variable, is often indicated with the letter $y$ .

With this notation, we write $y = f(x)$ , read "y is a function of x", in the sense that the value of the variable y depends on the value of the variable x, and f is the function that tells you how y depends on x.

In your example, you have $y = f(x) = 2-4x$ , which means "subtract four times the input (4x) from 2"

So, it doesn't matter which input you chose (i.e. the value for x), because you will always have to behave this way:

Pick an input value, x
Multiply it by four to get 4x
Subtract this number from 2: 2-4x

Here are some examples of explicit calculations: if I choose $x = 2$ and input, the workflow will be

Pick an input value, 2
Multiply it by four to get 8
Subtract this number from 2: 2-8=-6

So, if the input is 2, the output is -6

Similarly, if we choose $x = 0$ as input, we have:

Pick an input value, 0
Multiply it by four to get 0
Subtract this number from 2: 2-0=2

So, if the input is 0, the output is 2. And so on: for every possible value for x you have the correspondant value for y, with the function f telling you how to associate one with the other.

4 0

3 years ago

The equation of the line that goes through the points ( − 3 , − 9 ) and ( − 6 , − 3 ) can be written in the form y = m x + b

ivolga24 [154]

Answer:

$y=-2x-15$

Step-by-step explanation:

$y=mx+b$ .

m is the slope of the line. To find it we can do $\frac{dy}{dx}$ which is the difference between the y-coordinates divided by the difference between the x-coordinates.

So: $\frac{dy}{dx} =\frac{-9-(-3)}{-3-(-6)} =\frac{-6}{3} =-2$ . Now we have the slope, let's input a set of coordinates into the equation so that we can find the constant $b$ .