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vovangra [49]
2 years ago
12

I am confused with this word problem.

Mathematics
1 answer:
bazaltina [42]2 years ago
8 0

Answer:

30pgs=$20

42pgs=$26

Step-by-step explanation:

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Use exponents to write 81 three different ways.
nlexa [21]
Answer:.81 , 81%,81/100
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2 years ago
Write y2 in isolated<br> form.<br> 19x2 + 4y2 = 25
Bogdan [553]
Y=(-19x+5)/4 thats your answer
6 0
3 years ago
Sovle 7 pls and thankyou
Alina [70]

Answer:

-2r^7x^2

Step-by-step explanation:

-6x^3r^7/3x

2r^7x^3/X

4 0
3 years ago
(08.01)
pogonyaev

Answer:

(1.4), because both lines pass through this point

Step-by-step explanation:

3 0
3 years ago
an oil company conducts a geological study that indicates that an exploratory oil well should have a 20% chance of striking oil.
bazaltina [42]

Answer:

4.92% probability that the third strike comes on the seventh well drilled

Step-by-step explanation:

For each drill, there are only two possible outcomes. Either it is a strike, or it is not. Each drill is independent of other drills. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

20% chance of striking oil.

This means that p = 0.2

What is that probability that the third strike comes on the seventh well drilled

2 stikers during the first 6 drills(P(X = 2) when n = 6)[/tex]

Strike during the 7th drill, with 0.2 probability. So

P = 0.2P(X = 2)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{6,2}.(0.2)^{2}.(0.8)^{4} = 0.2458

Then

P = 0.2P(X = 2) = 0.2*0.2458 = 0.0492

4.92% probability that the third strike comes on the seventh well drilled

3 0
3 years ago
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