The angle next to the angle 5x is 180 - 5x
All angles sum to 360
(6x - 58) + (2x + 4) + (180 - 5x) = 180
3x + 126 = 180
3x = 54
x = 18
For question 10, sum of angles in pentagon is 540 degrees
x + 105 + 85 + 114 + 126 = 540
x + 430 = 540
x = 110
Side of the original square is 5 cm.
Step-by-step explanation:
- Step 1: Let the side of the original square be x. Then side of the new square = x + 3 and Area of new square = 64 cm²
Area of a square = (side)²
⇒ 64 = (x + 3)²
⇒ 64 = x² + 6x + 9
⇒ x² + 6x - 55 = 0
⇒ x² + 11x - 5x - 55 = 0 (Since 6x = 11x - 5x as part of factorizing)
⇒ x(x + 11) - 5(x + 11) = 0
⇒ (x + 11)(x - 5) = 0
⇒ x = -11 and x = 5 (Lengths can't be negative)
Side of the original square is 5 cm.
Answer:
<h2>9p</h2>
Step-by-step explanation:
9p - 8 + 8
9p - 0
9p
-8 + 8 cancel out.
9p is a variable, and its own term with no like terms. so you leave it alone.
That gives you 9p
Hope that helps!
Answer:
2y + 6
Step-by-step explanation:
2(y - 1) + 8
2y - 2 + 8
= 2y + 6
Answer:
The correct options are:
Interquartile ranges are not significantly impacted by outliers.
Lower and upper quartiles are needed to find the interquartile range.
The data values should be listed in order before trying to find the interquartile range.
The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range.
The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median
