Answer:
= 4 whole 1/2
Step-by-step explanation:
Given that:
= −36/−8
"-" signs will be cancelled out with each other so
= 36/8
By reducing to lowest term
= 9/2
When writing into mixed form:
quotient = 4, remainder = 1, divisor = 2 so:
= 4 1/2
i hope it will help you!
Answer:
12π ft², B
Step-by-step explanation:
Area of circle: radius²π
The area of the entire circle would thus be 6²π, or 36π
Note that a circle has a total degree measure of 360°, and the shaded area is 120°. Thus, the area of the shaded region would be 120/360 of the circle's area, or 1/3.
1/3 * total area of the circle = area of the shaded region
1/3 * 36π = 12π
Thus, the answer is 12π ft², or B.
Given:
In parallelogram ABCD, two of its vertices are A(-4,0) and B(0,3).
To find:
The equation that represents a line that contain CD.
Solution:
We have,
A(-4,0) and B(0,3)
Slope of AB is



The slope of line AB is
.
Opposite sides of a parallelogram are parallel and slopes of parallel lines are equal.
In parallelogram ABCD, AB and CD are opposite sides. So, their slopes must be equal.
Slope of line AB = Slope of line CD = 
The slope intercept form of a line is

Where, m is slope and b is y-intercept.
Slope of line CD is
, it means the line must be of the form

Coefficient of x is
only in option a.
Therefore, the correct option is a.
Answer:
<u>135.94 feet</u>
Step-by-step explanation:
Split the problem into two parts :
- Distance between viewer and building
- Height of the top part of the building
<u>Distance between viewer and building</u>
- The lower part of the building is 40 feet, as it is mentioned the viewer is 40 feet above street level
- Let the distance be called 'd'
- Therefore, tan37° = 40/d
- tan37° = 3/4 = 0.75
- ⇒ 40/d = 0.75
- ⇒ d = 40/(3/4) = 40 x 4/3 = 160/3 = 53.3 feet
<u>Height of the top part of the building</u>
- Let the height of the top part be 'h'
- Therefore, tan61° = h/d = h/53.3
- tan61° = 1.8
- ⇒ h/53.3 = 1.8
- ⇒ h = 53.3 x 1.8 = 95.94 feet
<u>Total height of building</u>
- Lower part + Top part
- 40 + 95.94
- <u>135.94 feet</u>
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