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prisoha [69]
3 years ago
9

The graph of a line is shown below. What is the equation of the line, in slope-intercept form, that is parallel to this line and

has a y-intercept of 1?

Mathematics
1 answer:
dimulka [17.4K]3 years ago
6 0

Answer:

y =  -  \frac{3}{2} x + 1

Step-by-step explanation:

Slope -intercept form: y= mx +c, where m is the slope and c is the y-intercept.

Parallel lines have the same slope. Let's find the slope of the given line.

Given points: (-2, 0) and (0, -3)

\boxed{slope =  \frac{y1 - y2}{x1 - x2} }

slope of given line

=  \frac{0 - ( - 3)}{ - 2 - 0}

=  \frac{0 + 3}{ - 2}

=   - \frac{3}{2}

y =  -  \frac{3}{2} x + c

Given that the y- intercept is 1, c= 1.

y =  -  \frac{3}{2} x + 1

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CAN SOMEONE PLEASE WRITE A EQUATION OF THIS LINE!!
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Answer (<u>assuming it can be in slope-intercept form)</u>:

y = -x - 1

Step-by-step explanation:

When knowing the slope of a line and its y-intercept, you can write an equation to represent it in slope-intercept form, or y = mx + b format. Substitute the m and b for real values.

1) First, find the slope of the equation, or m. Pick any two points from the line and substitute their x and y values into the slope formula, m = \frac{y_2-y_1}{x_2-x_1}. I chose the points (0, -1) and (-1, 0):

m = \frac{(0)-(-1)}{(-1)-(0)} \\m = \frac{0+1}{-1-0} \\m = \frac{1}{-1} \\m = -1

Thus, the slope is -1.

2) Now, find the y-intercept, or b. The y-intercept of a line is the point at which the line crosses the y-axis. By reading the graph, we can see that the line intersects the y-axis at the point (0,-1), therefore that must be the y-intercept.  

3) Now, substitute the found values into the y = mx + b formula. Substitute -1 for m and -1 for b:

y = -x  -1

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