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asambeis [7]
3 years ago
7

How strong is the electric field between two parallel plates 5.8 mm apart if the potential difference between them is 200 V?

Physics
2 answers:
crimeas [40]3 years ago
7 0

Answer: Electric field is given as

E = V/d

E = 220 v / 0.0056m

E = 39285.71 v/m

Or

E = 39285.71 N/C

Explanation: Therefore electric field is 39285.71 V/m

Liono4ka [1.6K]3 years ago
4 0

Answer:

Answer: Electric field is given as

E = V/d

E = 220 v / 0.0058m

E = 37931.03 v/m

Or

E = 37931.03 N/C

Explanation:

e=v/d

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what’s 55mph to km/min? can someone explain to to me with the work so i can understand how to solve this
natali 33 [55]

Answer:

55 miles / hour = 1.475232 kilometers / minute

6 0
3 years ago
Read 2 more answers
The critical angle for a substance is measured at 53.7 degrees. light enters from air at 45.0 degrees. at what angle it will con
faust18 [17]
When light travels from a medium with greater refractive index n_1 to a medium with smaller refractive index n_2, there exists an angle (called critical angle) above which the light is totally reflected, and the value of this angle is given by
\theta_c = \arcsin ( \frac{n_2}{n_1} )
In this problem, we know that the critical angle is\theta_c = 53.7^{\circ}, so we can find the ratio between the refractive indices of the two mediums:
\frac{n_2}{n_1} = \sin \theta_c = \sin 53.7^{\circ} =0.81
and since the second medium is air (n=1.00), the refractive index of the first medium is
n_1=  \frac{n_2}{0.81}= \frac{1.00}{0.81}=1.23

In the second part of the problem, we have light entering from air (n_i = 1.00) at angle of incidence of \theta_i = 45.0 ^{\circ}, into the second medium with n_r = 1.23. By using Snell's law, we can find the angle of refraction of the light inside the medium:
n_i \sin \theta_i = n_r \sin \theta_r
\sin \theta_r =  \frac{n_i}{n_r}  \sin \theta_i = \frac{1.00}{1.23} \sin 45^{\circ}=0.574
\theta_r = \arcsin(0.574)=35.1^{\circ}
3 0
3 years ago
Which of the following is typically NOT a method scientist use to determine astronomic distances
tangare [24]
I think the answer is A
5 0
3 years ago
You measure the pressure of the four tires of your car each to be 35.0 pounds per square inch (psi). You then roll your car forw
Oksi-84 [34.3K]

Answer:

Weight of car = 36034.88 lb.ft/s²

Explanation:

We are told the pressure of the four tires of your car is; P = 35.0 psi

Also, the surface area of contact is; A = 32 in²

Thus;

Weight of tires = Pressure × Area

W_tires = 35 × 32

Weight_tires = 1120lb.

To get the weight of the car, we will multiply the tire weight by acceleration due to gravity.

It's value in ft/s² is g = 32.174 ft/s²

Thus;

Weight of car = 1120 × 32.174

Weight of car = 36034.88 lb.ft/s²

5 0
3 years ago
A negative charge of -0.550 m exerts an upward <a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="5868766e
almond37 [142]

Answer:

a. +10.9μC

b. 0.600N and downward

Explanation:

To determine the magnitude of the charge, we use the force rule that exist between two charges which us expressed as

F=(kq₁q₂)/r²

since q₁=-0.55μC and the force it applied on the charge above it is upward,we can conclude that the second charge is +ve, hence we calculate its magnitude as

q₂=Fr²/kq₁

q₂=(0.6N*0.3²)/(9*10⁹*0.55*10⁻⁶)

q₂=0.054/4950

q₂=1.09*10⁻⁵c

q₂=10.9μC.

Hence the second charge is +10.9μC

b. From the rule of charges which state that like charges repel and unlike charges attract, we can conclude that the two above charges will attract since they are unlike charges. Hence the direction of the force will be downward into the second charge and the magnitude of the force will remain the same as 0.600N

8 0
4 years ago
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