All categories

3 years ago

Starting over, so here's some points! Take em last dayyy ~Jayden

Physics

2 answers:

masya89 [10]3 years ago

3 0

Answer:

Thank you so much!!!! :D

Anit [1.1K]3 years ago

3 0

thank you so much! i really appreciate it

You might be interested in

A rug sits in a sunny place on the floor for a long time. Kiara thinks that light from the sun can cause the rug’s color to fade

laiz [17]

Answer:

Yes, the sun can fade the color of the rug.

Explanation:

6 0

2 years ago

When you ride a bicycle, in what direction is the angular velocity of the wheels? When you ride a bicycle, in what direction is

Hitman42 [59]

Complete question is;

When you ride a bicycle, in what direction is the angular velocity of the wheels? A) to your left B) to your right C) forwards D) backwards

Answer:

Option A - to your left

Explanation:

While an object rotates, each particle will have a different velocity:

the 'Speed' component will vary with radius while the 'Direction' component will vary with angle.

All of the velocity vectors are aligned in the same plane.

We can be solve this by choosing a single vector normal to ALL of the possible velocity vectors of the rotating object in that plane.

This convention used is known as "Right-hand rule". The angular velocity vector points along the wheel's axle. For instance, if you Imagine wrapping your right hand around the axle so that your fingers point in the direction of rotation, with your thumb sticking out. You will notice that your thumb points to the left.

Thus;

By right-hand rule, a wheel rotating on a forward - moving bicycle has an angular velocity vector pointing to the rider's left.

So, option A is the correct answer

3 0

4 years ago

An accelerating voltage of 2.42 103 V is applied to an electron gun, producing a beam of electrons originally traveling horizont

Pavlova-9 [17]

Answer:

Part (a) The magnitude of the deflection of electron beam on the screen due to the Earth's gravitational field is 5.97* $10^{-16}$ m.

Part (b) The magnitude of the deflection of electron beam on the screen due to the vertical component of the Earth's magnetic field is $6.19* 10^-3$ m

6 0

3 years ago

The Hubble Space Telescope orbits the Earth at approximately 612,000m altitude. Its mass is 11,100 kg and the mass of earth is 5

nexus9112 [7]

Answer:

7.55 km/s

Explanation:

The force of gravity between the Earth and the Hubble Telescope corresponds to the centripetal force that keeps the telescope in uniform circular motion around the Earth:

$G\frac{mM}{R^2}=m\frac{v^2}{R}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}$ is the gravitational constant

$m=11,100 kg$ is the mass of the telescope

$M=5.97\cdot 10^{24} kg$ is the mass of the Earth

$R=r+h=6.38\cdot 10^6 m+612,000 m=6.99\cdot 10^6 m$ is the distance between the telescope and the Earth's centre (given by the sum of the Earth's radius, r, and the telescope altitude, h)

v = ? is the orbital velocity of the Hubble telescope

Re-arranging the equation and substituting numbers, we find the orbital velocity:

$v=\sqrt{\frac{GM}{R}}=\sqrt{\frac{(6.67\cdot 10^{-11})(5.97\cdot 10^{24} kg)}{6.99\cdot 10^6 m}}=7548 m/s=7.55 km/s$

6 0

3 years ago

A thin, circular hoop with a radius of 0.22 m is hanging from its rim on a nail. When pulled to the side and released, the hoop

Alex73 [517]

Answer:

Period of oscillation = 1.33 seconds

Explanation:

The period of oscillation is given by:

T = 2π√[I/(MgL)]

for I = 2MR² and L = R,

Given: L = 0.22m = R

T = 2π√[2R/g]

T = 2 × 3.142 Sqrt[( 2 × 0.22)/ 9.8]

T = 6.284 Sqrt(0.44/9.8)

T = 6.284 Sqrt(0.0449)

T = 6.284 × 0.2119

T = 1.33 sec

6 0

4 years ago