Given:
m∠NRQ = 60°
To find:
The angle measure of minor arc NQ
Solution:
The inscribed angle is half of the intercepted arc.

Multiply by 2 on both sides.


Substitute m∠NRQ = 60°.


The measure of minor arc NQ is 120°.
Answer:
add 15 to both sides
Step-by-step explanation:


To solve for the area of a triangle, we multiply the length and height, then divide that by two. L = 10. H = 7.



To solve for the perimeter, or edges, of the triangle, we need to use the Pythagorean Theorem: a² + b² = c² to solve for the third side. We already know two measures: 10 and 7. Now we need to square them, add them together to get c², then take the root of that number.

We cannot simplify √149, so we either leave it, or round it.

This is rounded to the nearest 10,000.

Now that we have the measure of the longest side, we can add all three sides together to get the perimeter of the triangle.


Y = x - 1
y = -5 - 1
y = -6
(x, y) = (-5, -6)
y = x - 1
y = -3 - 1
y = -4
(x, y) = (-3, -4)
y = x - 1
y = 0 - 1
y = -1
(x, y) = (0, -1)
y = x - 1
y = 1 - 1
y = 0
(x, y) = (1, 0)
y = x - 1
y = 2 - 1
y = 1
(x, y) = (2, 1)