M+4n=8
m=n-2
we see that m=n-2
so we can subsitute 'n-2' for m in the first equation
(n-2)+4n=8
n-2+4n=8
5n-2=8
add 2 to both sides
5n=10
divide by 5
n=2
subsitute
n=2
m=n-2
m=2-2
m=0
m=0
n=2
the answer is c. 0,2
(3,-1) for sure i took the test 100%
hope i helped out
The consecutive positive integers would be: x and (x+1),
We would have to solve the following equation to find these numbers:
x(x+1)-[x+(x+1)]=29
x²+x-2x-1=29
x²-x-30=0
x=[1⁺₋√(1+120)]/2
x=(1⁺₋11)/2
We have two possible solutions:
x₁=(1-11)/2=-5 then: (x+1)=-5+1=-4 This is not the solution.
x₂=(1+11)/2=6 then: (x+1)=6+1=7 This solution is right.
Answer: the numbers would be 6 and 7.
Step-by-step explanation:
assuming two points with coordinates :
(Xa,Ya) and (Xb,Yb)
use formula : (Xb-Xa)/ (Yb-Ya)
= 5+1/-3-1 = 6/-4
the standard form is 6/-4 × x
8 and 2/3 because each whole can be split to 3/3 :)
