I believe the fastest way to solve this problem is to take any two of the given points and to find the slope and y-intercept of the line connecting those two points.
Let's choose the 2 given points (-3,16) and (-1,12).
Going from the first point to the second, the increase in x is 2 and the increase in y is actually a decrease: -4. Thus, the slope of the line connecting these two points is m = -4/2, or m = -2.
Now use the slope-intercept formula to find the y-intercept, b.
One point on the line is (-3,16), and the slope is m = -2.
Thus, the slope-intercept formula y = mx + b becomes 16 = -2(-3) + b.
Here, b comes out to 10.
So now we have the slope and the y-intercept. Write the equation:
y = mx + b becomes y=-2x+10. Which of the four given answer choices is the correct one?
Step-by-step explanation:
Statement:
2-) ∠BAC = ∠EDC
<em>Reason:</em>
Angles opposite to equal sides of a triangle are equal (Alternate Interior Angles Theorem)
Statement:
3-) AC = CD
<em>Reason:</em>
CPCTC ("Corresponding Parts of Congruent Triangles are Congruent")
Statement:
4-) ∠BCA = ∠DCE
<em>Reason:</em>
Vertical Angles Theorem (states that vertical angles, angles that are opposite each other and formed by two intersecting straight lines, are congruent)
Statement:
5-) triangle ABC = triangle DEC
ASA Postulate
The ASA (Angle-Side-Angle) postulate states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent. (The included side is the side between the vertices of the two angles.)
<h2>22</h2><h3>Answer: B</h3><h3 /><h2>23</h2><h3>Answer: D</h3><h3 /><h2>24</h2><h3>Answer: A</h3><h3 /><h2>25</h2><h3>Answer: C</h3>
Answer:
A. U - 2v = -14i +13j
Step-by-step explanation:
If u = (-2, 5) and v = 6i -4j
Then 2v = 2*(6i-4j) = 12i-8j
u-2v = -2i +5j - (6i -4j)
Distribute the minus sign
-2i +5j -6i+4j
-2i +5j
-12i + 8j
---------------
-14i +13j
Answer:
The given expression can't be expressed in polynomial form. Hence, it is not a polynomial.
Step-by-step explanation:
P(x,n) is a polynomial of nth degree if it is of the form,
P(x,n) = 
where n is a finite positive integer and n ∈ N
and '
's are fixed but otherwise arbitrary constants ∀ i = 0(1)n .
Now, the given expression is,
which doesn't fit in the above form. Hence, it is not a polynomial.
Answer:
tehe
Step-by-step explanation:
tehetehetehetehe
