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mars1129 [50]
3 years ago
9

A fishing trawler sails from port P in the direction 024o for 30 km, and then in the direction 114o for 20 km. Calculate: a) the

distance and bearing of the trawler from P b) the direction in which the trawler must sail in order to return to P
Please use diagrams to explain.
Mathematics
1 answer:
JulijaS [17]3 years ago
4 0

Answer:

write these time in words 3:45

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If y=(x^2-4)^5(3x+4)^4
alexira [117]

Answer:

y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)

Step-by-step explanation:

y=(x^2-4)^5(3x+4)^4

y'=[\frac{d}{dx}(x^2-4)^5](3x+4)^4+(x^2-4)^5[\frac{d}{dx}(3x+4)^4]

y'=10x(x^2-4)^4(3x+4)^4+(x^2-4)^5(12(3x+4)^3)

y'=10x(x^2-4)^4(3x+4)^4+12(x^2-4)^5(3x+4)^3

y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)

5 0
2 years ago
hi um can you tell me where i am supposed to put the 2 points? i know that the first one goes on the 0 but where do i but the 2n
Nina [5.8K]

Answer:

114.75

Step-by-step explanation:

You just multiply 25.50 by 4.50 :))

Hope this helps and sorry if I'm wrong.

Have a wonderful rest of your day. <3

8 0
3 years ago
2895÷229=<br> PLZ RIGHT WITH WHOLE NUMBER AND REMANDER<br> ---<br> R:
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Step-by-step explanation:

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Label the points, lines, and planes to show AB←→ and line j perpendicular to each other in plane R at point A, AB←→ both perpend
algol [13]

Answer:

That would be c

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Read 2 more answers
X^4 + x^3 + x^2 + x=0
kifflom [539]
X^4 + x^3 + x^2 + x = 0

x(x^3 + x^2 + x + 1) = 0

x[x^2(x + 1) + 1(x + 1)] = 0

x(x + 1)(x^2 + 1) = 0 ⇔ x = 0 or x + 1 = 0 or x^2 + 1 = 0

x = 0 or x = -1 or x^2 = -1 -false

Answer: x= 0 or x = -1.
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