Answer:
f) a[n] = -(-2)^n +2^n
g) a[n] = (1/2)((-2)^-n +2^-n)
Step-by-step explanation:
Both of these problems are solved in the same way. The characteristic equation comes from ...
a[n] -k²·a[n-2] = 0
Using a[n] = r^n, we have ...
r^n -k²r^(n-2) = 0
r^(n-2)(r² -k²) = 0
r² -k² = 0
r = ±k
a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q
We find p and q from the initial conditions.
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f) k² = 4, so k = 2.
a[0] = 0 = p + q
a[1] = 4 = -2p +2q
Dividing the second equation by 2 and adding the first, we have ...
2 = 2q
q = 1
p = -1
The solution is a[n] = -(-2)^n +2^n.
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g) k² = 1/4, so k = 1/2.
a[0] = 1 = p + q
a[1] = 0 = -p/2 +q/2
Multiplying the first equation by 1/2 and adding the second, we get ...
1/2 = q
p = 1 -q = 1/2
Using k = 2^-1, we can write the solution as follows.
The solution is a[n] = (1/2)((-2)^-n +2^-n).
A= 2.5
b= 2
LM/ON= 15
LO/MN= 5
Answer:
b=5m+r/m
Step-by-step explanation:
Let's solve for b.
r=(b−5)(m)
Step 1: Flip the equation.
bm−5m=r
Step 2: Add 5m to both sides.
bm−5m+5m=r+5m
bm=5m+r
Step 3: Divide both sides by m.
bm/m=5m+r/m
b=5m+r/m
Answer:
b=5m+r/m
Answer: infinitely many solutions.
Step-by-step explanation:
Ok, our equation is:
-2.1*b + 5.3 = b - 3.1*b + 5.3
now, simplifyng the right side, we have:
b - 3.1*b + 5.3 = (1 - 3.1)*b + 5.3 = -2.1*b + 5.3
Then our initial expression is:
-2.1*b + 5.3 = -2.1*b + 5.3
So in both sides of the equality we have the exact same thing, so this is a trivial equality.
This means that the equality will remain true for any value of b, which means that we have infinitely many solutions.
Answer:
The answer is D.
Step-by-step explanation:
The difference between each term is 4.
-2 - (-6) = 4
2 - (-2) = 4
6 - 2 = 4
10 - 6 = 4
