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3 years ago

11

Ross, a college sophomore, has no clear preference for any of the candidates running for student body president. The students he

admires most are campaigning for their fraternity brother, Henry. Ross decides to support Henry as well. This most reflects ____.

1 answer:

mylen [45]3 years ago

7 0

Answer:

longing for social inclusion.

Explanation:

Ross here is longing for social inclusion.

He decides to campaign for the his fraternity brother not by choice or will but by peer pressure and social inclusion because most of the students campaigned for Henry so he supports Henry as well. Moreover, he did not be feel left out and he did not have a clear preference as well.

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A 1.60 m cylindrical rod of diameter 0.550 cm is connected to a power supply that maintains a constant potential difference of 1

bija089 [108]

1.

Answer:

Part a)

$\rho = 1.35 \times 10^{-5}$

Part b)

$\alpha = 1.12 \times 10^{-3}$

Explanation:

Part a)

Length of the rod is 1.60 m

diameter = 0.550 cm

now if the current in the ammeter is given as

$i = 18.7 A$

V = 17.0 volts

now we will have

$V = I R$

$17.0 = 18.7 R$

R = 0.91 ohm

now we know that

$R = \rho \frac{L}{A}$

$0.91 = \rho \frac{1.60}{\pi(0.275\times 10^{-2})^2}$

$\rho = 1.35 \times 10^{-5}$

Part b)

Now at higher temperature we have

$V = I R$

$17.0 = 17.3 R$

R = 0.98 ohm

now we know that

$R = \rho \frac{L}{A}$

$0.98 = \rho' \frac{1.60}{\pi(0.275\times 10^{-2})^2}$

$\rho' = 1.46 \times 10^{-5}$

so we will have

$\rho' = \rho(1 + \alpha \Delta T)$

$1.46 \times 10^{-5} = 1.35 \times 10^{-5}(1 + \alpha (92 - 20))$

$\alpha = 1.12 \times 10^{-3}$

2.

Answer:

Part a)

$i = 1.55 A$

Part b)

$v_d = 1.4 \times 10^{-4} m/s$

Explanation:

Part a)

As we know that current density is defined as

$j = \frac{i}{A}$

now we have

$i = jA$

Now we have

$j = 1.90 \times 10^6 A/m^2$

$A = \pi(\frac{1.02 \times 10^{-3}}{2})^2$

so we will have

$i = 1.55 A$

Part b)

now we have

$j = nev_d$

so we have

$n = 8.5 \times 10^{28}$

$e = 1.6 \times 10^{-19} C$

so we have

$1.90 \times 10^6 = (8.5 \times 10^{28})(1.6 \times 10^{-19})v_d$

$v_d = 1.4 \times 10^{-4} m/s$

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3 years ago

According to Newton, which of these will determine if and how an object will move?

mr Goodwill [35]

Answer:

3

Explanation:

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A train travels with a constant speed of 28 miles per hour. How long will it take to travel a distance of 112 miles? Show your c

AVprozaik [17]

Answer:

4 hours

Explanation:

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3 years ago

True or false. gravity helps the Earth to stay in orbit around the sun

gogolik [260]

Answer:

The answer would be true

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3 years ago

Read 2 more answers

A small mirror is attached to a vertical wall, and it hangs a distance of 1.87 m above the floor. The mirror is facing due east,

Oksana_A [137]

Answer:

t = 1.62 h

Explanation:

A flat mirror fulfills the law of reflection where the incident angle is equal to the reflected angle.

θ_i = θ_r

If we use trigonometry to find the angles, the mirror is at a height of L = 1.87 m, and the reflected rays reach a distance x1 = 3.56 m

tan θ₁ = x₁ / L

tan θ₁ = $\frac{3.56}{1.87}$

θ₁ = tan⁻¹ 1.90

θ₁ = 62.29º

for the second case x₂ = 1.46 m

tan θ₂ = x₂ / L

θ₂ = tan⁻¹ $\frac{1.46}{1.87}$

θ₂ = 37.98º

the difference in degree traveled is

Δθ = θ₁- θ₂

Δθ = 62.29 - 37.98

Δθ = 24.31º

as in the exercise they indicate that every 15º there is an hour

t = 24.31º (1h / 15º)

t = 1.62 h

4 0

3 years ago