Answer:
I₂ = 2.13 x 10⁻⁸ W/m²
Explanation:
given,
increase in sound level = 28.1 dB
frequency of the sound = 250 Hz
intensity = 3.3 x 10⁻¹¹ W/m²
Intensity delivered = ?
the difference of intensity level is give as
I₂ = 645.65 I₁
I₂ = 645.65 x 3.3 x 10⁻¹¹
I₂ = 2.13 x 10⁻⁸ W/m²
Answer: The voids between stars in our galaxy can be filled with tenuous clouds of gas and other molecules. ... That material gets "ripped away" from the galaxies by the force of gravity, and often enough it collides with other material.
HOPE IT HELPED:) HAVE A NICE DAY
Answer:
Gay-Lussac’s law, because as the pressure increases, the temperature increases
Explanation:
First of all, we can notice that the volume of the tank is fixed: this means that the volume of the air inside is also fixed.
This means that in this situation we can apply Gay-Lussac's law, which states that:
"for a gas kept at constant volume, the pressure of the gas is proportional to the absolute temperature of the gas".
Mathematically:
where p is the pressure in Pascal and T is the temperature in Kelvin.
In this case, the tank is filled with air: this means that the pressure of the gas inside the tank increases. And therefore, according to Gay-Lussac's law, the temperature will increase proportionally, and this explains why the tank gets hot.
Answer:
2583.9 N/C
Explanation:
Parameters given:
Outer diameter = 14 cm
Outer radius, R = 7cm = 0.07m
Inner diameter = 7 cm
Inner radius, r = 3.5 cm = 0.035m
Charge of washer = 8 nC = 8 * 10^(-9)C
Distance from washer, z = 33 cm = 0.33m
The electric field due to a washer (hollow disk) is given as:
E = k * σ * 2π [ 1 - z/(√(z² + R²)]
Where σ = charge per unit area
σ = q/π(R² - r²)
σ = 8 * 10^(-9) /(π*(0.07 - 0.035)²)
σ = 2.077 * 10^(-6) C/m²
=> E = 9 * 10^9 * 2.077 * 10^(-6) * 2π * [1 - 0.33/(√(0.33² + 0.07²)]
E = 117.467 * 10^3 * (1 - 0.978)
E = 117.467 * 10^3 * 0.022
E = 2583.9 N/C
wave function of a particle with mass m is given by ψ(x)={ Acosαx −
π
2α
≤x≤+
π
2α
0 otherwise , where α=1.00×1010/m.
(a) Find the normalization constant.
(b) Find the probability that the particle can be found on the interval 0≤x≤0.5×10−10m.
(c) Find the particle’s average position.
(d) Find its average momentum.
(e) Find its average kinetic energy −0.5×10−10m≤x≤+0.5×10−10m.
